汇编程序2:问题2.3分析

 1 问题2.3 2 初始值:CS = 2000H,IP = 0000H,AX = 0,BX = 0
 3 第一次执行:mov ax,6622H
 4         CS = 2000H,IP = 0003H,AX = 6622H,BX = 0
 5 第二次执行:jmp 1000:3
 6         CS = 1000H,IP = 0003H,AX = 6622H,BX = 0
 7 第三次执行:mov ax,0000
 8         CS = 1000H,IP = 0006H,AX = 0,BX = 0
 9 第四次执行:mov bx,ax
10         CS = 1000H,IP = 0008H,AX = 0,BX = 0
11 第五次执行:jmp bx
12         CS = 1000H,IP = 0000H,AX = 0,BX = 0
13 第六次执行:mov ax,0123H
14         CS = 1000H,IP = 0003H,AX = 0123H,BX = 0
15 第七次执行:转到第三步继续执行

 

posted on 2018-01-24 17:09  叶倾仙  阅读(162)  评论(0编辑  收藏  举报

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