一、PHP/MySQL编程
1) 某内容管理系统中,表message有如下字段
id 文章id
title 文章标题
content 文章内容
category_id 文章分类id
hits 点击量
创建上表,写出MySQL语句

2)同样上述内容管理系统:表comment记录用户回复内容,字段如下
comment_id 回复id
id 文章id,关联message表中的id
comment_content 回复内容
现通过查询数据库需要得到以下格式的文章标题列表,并按照回复数量排序,回复最高的排在最前面

文章id 文章标题 点击量 回复数量

 

用一个SQL语句完成上述查询,如果文章没有回复则回复数量显示为0

3) 上述内容管理系统,表category保存分类信息,字段如下
category_id int(4) not null auto_increment;
categroy_name varchar(40) not null;
用户输入文章时,通过选择下拉菜单选定文章分类
写出如何实现这个下拉菜单

drop table if exists Comment;

drop table if exists category;

drop table if exists message;

/**//*==============================================================*/
/**//* Table: Comment                                               */
/**//*==============================================================*/
create table Comment
(
    comment_id                     
int unsigned                   not null,
    id                             
int unsigned                   not null,
    comment_content                
text,
   
primary key (comment_id)
)
type
= InnoDB;

/**//*==============================================================*/
/**//* Table: category                                              */
/**//*==============================================================*/
create table category
(
    category_id                    
int                            not null AUTO_INCREMENT,
    category_name                  
varchar(40)                    not null,
   
primary key (category_id),
   
key AK_pk_category_id (category_id)
)
type
= InnoDB;

/**//*==============================================================*/
/**//* Table: message                                               */
/**//*==============================================================*/
create table message
(
    id                             
int                            not null,
    title                          
varchar(120)                   not null,
    content                        
text                           not null,
    category_id                    
int unsigned,
    hit                            
int unsigned,
   
primary key (id)
)
type
= InnoDB;

select A.id,A.title,A.hits,IFNULL(B.num,0)
from message A left join (select id,count(*) as num from comment B group by id) B
on A.id=B.id
order by B.num desc;

 

<html>
<head><title>JS打印</title></head>
<body>
<form>
<select id="category" name="category">
<?php
mysql_connect("localhost","root","") or die("db conn error:".mysql_error());
mysql_select_db("phpinterview") or die("db error".mysql_error());
$result=mysql_query("select category_id,category_name from category");
while($row=mysql_fetch_array($result))
{
    
echo "<option value='".$row["cateogry_id"]."'>".$row["category_name"]."</option>";
}
?>
</select>
</form>
</body>
posted on 2010-04-20 10:53  钱途无梁  阅读(1620)  评论(0编辑  收藏  举报