CodeForces 173C Spiral Maximum
题意:给你一个n*m的矩阵,然后问你螺旋线能够覆盖的最大和是多少
思路:
暴力记忆化搜索,滚动数组优化
dp[i][j][len]表示以i,j为起点,正方形边长为len的覆盖的值是多少
dp[i][j][len]显然等于len所在的正方形覆盖的和 - mp[i+1][j] - dp[i+1][j+1][len-2]
#include<bits/stdc++.h> using namespace std; #define INF 1e9 int n,m; int mapp[510][510]; int sum[510][510]; int vis[510][510]; int dp[510][510][2]; int cal(int x1,int y1,int x2,int y2) { return sum[x2][y2]-sum[x1-1][y2]-sum[x2][y1-1]+sum[x1-1][y1-1]; } int solve(int x,int y,int len) { if (len==0) { dp[x][y][0]=mapp[x][y]; return dp[x][y][0]; } else { dp[x][y][0]=cal(x,y,x+len,y+len); dp[x][y][0]-=mapp[x+1][y]; dp[x][y][0]-=dp[x+1][y+1][1]; return dp[x][y][0]; } } int main() { scanf("%d%d",&n,&m); for (int i = 1;i<=n;i++) for (int j = 1;j<=m;j++) scanf("%d",&mapp[i][j]); for (int i = 1;i<=n;i++) for (int j = 1;j<=m;j++) sum[i][j]=mapp[i][j]+sum[i-1][j]+sum[i][j-1]-sum[i-1][j-1]; int ans = -INF; for (int k = 0;k<=min(n,m);k+=2) { memset(vis,0,sizeof(vis)); for (int i = n;i>=1;i--) for (int j = m;j>=1;j--) dp[i][j][1]=dp[i][j][0]; for (int i = n;i>=1;i--) { if (i+k>n) continue; for (int j = m;j>=1;j--) { if (j+k>m) continue; int p = solve(i,j,k); if (k>0) ans = max(ans,p); } } } printf("%d\n",ans); }