6月第三天

判断下列语句的True,False
1.1 > 1 or 3 < 4 or 4 > 5 and 2 > 1 and 9 > 8 or 7 < 6    True
2.not 2 > 1 and 3 < 4 or 4 > 5 and 2 > 1 and 9 > 8 or 7 < 6   False

求出下列语句的值
1.8 or 3 and 4 or 2 and 0 or 9 and 7       8
2.0 or 2 and 3 and 4 or 6 and 0 or 3       4

下列结果是什么
1.6 or 2 > 1    6
2.3 or 2 > 1    3
3.0 or 5 < 4    False
4.5 < 4 or 3    3
5.2 > 1 or 6    True
6.3 and 2 > 1   True
7.0 and 3 > 1   0         and 与 or 相反
8.2 > 1 and 3   3
9.3 > 1 and 0   0
10.3 > 1 and 2 or 2 < 3 and 3 and 4 or 3 > 2    2

利用while写一个猜大小的游戏
设定值为66,让用户输入,如果比66大,就显示结果大了;如果比66小,就显示结果小了
如果输入等于66,显示正确,退出循环
count = 66
while True:
    num = int(input("请输入一个数字:"))
    if num > count:
        print("大了")
    elif num < count:
        print("小了")
    else:
        print("输入正确")
        break
在第四题的基础上,给用户3次机会,在3次之内猜对,显示猜对,退出循环;在3次之内没有猜对
则自动退出,显示你太笨了
count = 66
n = 1
while n <= 3:
    num = int(input("请输入一个数字:"))
    if num > count:
        print("大了")
    elif num < count:
        print("小了")
    else:
        print("输入正确")
        break
    print("你已经猜了%d" % n)
    n += 1
else:
    print("你太笨了")
while输出1 2 3 4 5 6 8 9 10
n = 1
while n <=10:
    if n !=7:
    print(n)
    n += 1

n = 1
while n <= 10:
    if n == 7:
        n += 1
        continue
    print(n)
    n += 1

七.求1-2+3-...99的和
count = 1
sum = 0
while count < 100:
    if count % 2 == 0:    #偶数
        sum = sum - count
    else:
        sum = sum + count
    count += 1
print(sum)



用户登入（三次输错机会）且每次输错时都会显示错误剩余次数
count = 1
while count <=3:
    username = input("请输入你的用户名：")
    password = input("请输入你的密码：")
    if username == 'alex' and password == 'sd':
        print("登入成功")
        break
    else:
        print("登入失败")
    print("还剩%d次" % (3 - count))
    count = count + 1
else:
    print("蠢")
广告
ad = input("请输入你的广告标语:")
if "最" in ad or '国家级' in ad or '第一' in ad or '稀缺' in ad:
    print("不合法")
else :
    print("合法")


作业