catch SocketException

https://stackoverflow.com/questions/32810051/cannot-catch-socketexception/32810079#32810079

https://github.com/dart-lang/sdk/issues/25518

 

 

2
 

Asynchronous errors can't be caught using try/catch(https://www.dartlang.org/docs/tutorials/futures/) at least unless you are using async/await(https://www.dartlang.org/articles/await-async/)

See also https://github.com/dart-lang/sdk/issues/24278

You can use the done future on the WebSocket object to get that error, e.g.:

import 'dart:async';
import 'dart:io';

main() async {
  // Connect to a web socket.
  WebSocket socket = await WebSocket.connect('ws://echo.websocket.org');

  // Setup listening.
  socket.listen((message) {
    print('message: $message');
  }, onError: (error) {
    print('error: $error');
  }, onDone: () {
    print('socket closed.');
  }, cancelOnError: true);

  // Add message, and then an error.
  socket.add('echo!');
  socket.addError(new Exception('error!'));

  // Wait for the socket to close.
  try {
    await socket.done;
    print('WebSocket donw');
  } catch (error) {
    print('WebScoket done with error $error');
  }
}

  

I get your point, but I don't understand why this is an asynchronous error. I mean, you get this error before starting to actually asynchronously listen to requests, right? – Alexandr Sep 27 '15 at 16:41
1
HttpServer.bind() is already async (returns a Future<HttpServer>) – Günter Zöchbauer Sep 27 '15 at 16:43
You are right, Gunter. Thank you for this! – Alexandr Sep 28 '15 at 5:35

 

 

 

 

posted @ 2019-05-07 16:30  CrossPython  阅读(436)  评论(0编辑  收藏  举报