JAVA获取当前请求的URL地址,包含请求链接中的参数

 

 

/**
     * 获得当前访问的URL路径
     * @param request
     * @return
     */
    public static String getLocation(HttpServletRequest request) {
        UrlPathHelper helper = new UrlPathHelper();
        StringBuffer buff = request.getRequestURL();
        String uri = request.getRequestURI();
        String origUri = helper.getOriginatingRequestUri(request);
        buff.replace(buff.length() - uri.length(), buff.length(), origUri);
        String queryString = helper.getOriginatingQueryString(request);
        if (queryString != null) {
            buff.append("?").append(queryString);
        }
        try {
            return new String(buff.toString().getBytes(), "iso-8859-1");
        } catch (UnsupportedEncodingException e) {
            return buff.toString();
        }
    }

 

js获取方式:https://www.cnblogs.com/pxblog/p/13737882.html

posted @ 2020-09-27 17:04  yvioo  阅读(7106)  评论(0编辑  收藏  举报