摘要: const int MAXN = 2e5 + 10; int a[MAXN]; int val[MAXN]; #define mid ((l + r)>>1) int L[MAXN << 5]; int R[MAXN << 5]; int cnt[MAXN << 5]; ll sum[MAXN << 阅读全文
posted @ 2021-04-10 01:53 purinliang 阅读(58) 评论(0) 推荐(0) 编辑