CTF-安恒19年二月月赛部分writeup

CTF-安恒19年二月月赛部分writeup

 

MISC1-来玩个游戏吧

题目：

第一关，一眼可以看出是盲文，之前做过类似题目

 

拿到在线网站解一下

??41402abc4b2a76b9719d911017c592，那么就奇怪了，这个？？是什么东西，数一下加上？？正好32位，应该是个MD5了，索性直接百度一下，

第一关答案出来了，试过了MD5值不对，hello是正确的，下一关。

第二关提示

没见过这种的，还是百度一下，

下载了这个脚本后执行命令

fastcoll_v1.0.0.5.exe -p C:\windows\notepad.exe -o D:\notepad1.exe D:\notepad2.exe

（因为没有规定文件名啥的就直接复制他的命令了）

直接将文件路径复制到文本框即可

Dear Professional ; Especially for you - this cutting-edge 
intelligence ! If you no longer wish to receive our 
publications simply reply with a Subject: of "REMOVE" 
and you will immediately be removed from our club . 
This mail is being sent in compliance with Senate bill 
2216 , Title 9 ; Section 306 ! THIS IS NOT MULTI-LEVEL 
MARKETING . Why work for somebody else when you can 
become rich as few as 35 weeks . Have you ever noticed 
more people than ever are surfing the web and people 
will do almost anything to avoid mailing their bills 
. Well, now is your chance to capitalize on this ! 
WE will help YOU decrease perceived waiting time by 
120% & decrease perceived waiting time by 140% . You 
can begin at absolutely no cost to you . But don't 
believe us ! Mrs Jones of Minnesota tried us and says 
"I was skeptical but it worked for me" . We assure 
you that we operate within all applicable laws . Because 
the Internet operates on "Internet time" you must act 
now ! Sign up a friend and your friend will be rich 
too . Warmest regards . Dear Cybercitizen , We know 
you are interested in receiving red-hot announcement 
! We will comply with all removal requests ! This mail 
is being sent in compliance with Senate bill 1619 ; 
Title 2 ; Section 301 . This is NOT unsolicited bulk 
mail ! Why work for somebody else when you can become 
rich within 53 MONTHS ! Have you ever noticed more 
people than ever are surfing the web and more people 
than ever are surfing the web . Well, now is your chance 
to capitalize on this . We will help you use credit 
cards on your website plus decrease perceived waiting 
time by 150% . The best thing about our system is that 
it is absolutely risk free for you ! But don't believe 
us ! Mrs Simpson of Washington tried us and says "Now 
I'm rich, Rich, RICH" . We assure you that we operate 
within all applicable laws ! We beseech you - act now 
! Sign up a friend and your friend will be rich too 
. Thank-you for your serious consideration of our offer 
! Dear Friend ; This letter was specially selected 
to be sent to you ! If you no longer wish to receive 
our publications simply reply with a Subject: of "REMOVE" 
and you will immediately be removed from our mailing 
list . This mail is being sent in compliance with Senate 
bill 2716 , Title 2 ; Section 306 ! This is a ligitimate 
business proposal . Why work for somebody else when 
you can become rich inside 33 weeks . Have you ever 
noticed more people than ever are surfing the web plus 
more people than ever are surfing the web . Well, now 
is your chance to capitalize on this ! WE will help 
YOU SELL MORE and process your orders within seconds 
. You can begin at absolutely no cost to you . But 
don't believe us ! Mrs Jones of Kentucky tried us and 
says "I was skeptical but it worked for me" ! This 
offer is 100% legal ! We implore you - act now . Sign 
up a friend and you'll get a discount of 50% . God 
Bless . 

题目提示了：需要一个在线的网站去解密，而这个网站使用了栅格密码。

栅格密码也没听说过，还是百度

搜索关键字Spam Mimic到网站 http://www.spammimic.com/解码

flag为：flag{a0dd1e2e6b87fe47e5ad0184dc291e04}

 

MISC2-简单的流量分析

题目：

过滤http协议，按照info排序一下

发现存在/xinhu/robots.txt

追踪http流到/xinhu/robots.txt

发现abc.html,继续跟进

发现MD5和两串DES

md5 0x99a98e067af6b09e64f3740767096c96

DES 0xb19b21e80c685bcb052988c11b987802d2f2808b2c2d8a0d    (129->143)

DES 0x684a0857b767672d52e161aa70f6bdd07c0264876559cb8b    (143->129)

继续向下分析，发现都是IPSec加密后的流量，尝试使用前面给的MD5和DES解密

wireshark进入Preference菜单下的Profile，找到ESP， 配置如下：

 

 此时再次过滤http发现有部分响应包带上了数字，102 108 转换为ASCII码则为f l 所以统一提取转换。

a = [102,108,97,103,123,50,55,98,48,51,98,55,53,56,102,50,53,53,50,55,54,101,53,97,57,56,100,97,48,101,49,57,52,55,98,101,100,125]
flag = ''
for i in a:
    flag +=chr(i)
print flag

flag：flag{27b03b758f255276e5a98da0e1947bed}

 

CRYPTO1-hahaha

题目：

压缩包题目，其实看到这压缩包里的短位CRC32应该就能猜出是CRC32爆破了

当然也可以一步一步排除一下

首先binwalk分析得出非伪加密，爆破的话没有提示，不理想。

所以直接上脚本

所以加起来就是tanny_is_very_beautifu1_

哈哈

按照给的提示，flag应该是flag{1or! 2or@ sechn}

然后给了sha1值，应该是要爆破了。。。

当时做到这里就停了，因为不会写脚本了

下面献上一叶飘零大佬的脚本

 

import itertools
import hashlib

def sha1(str):
    sha = hashlib.sha1(str)
    encrypts = sha.hexdigest()
    return encrypts
a1 = '1!'
a2 = '2@'
a3 = '{'
a4 = '}'
for str1 in itertools.combinations(a1,1):
    for str2 in itertools.combinations(a2,1):
        str3 = str1[0]+str2[0]+'sechn'
        for i in itertools.permutations(str3):
            tmp = (''.join(i))
            res = 'flag{'+tmp+'}'
            # print sha1(res)
            if sha1(res) == 'e6079c5ce56e781a50f4bf853cdb5302e0d8f054':
                print res
                break

flag:flag{sh@1enc}

 小结：web没做出来太菜，pwn刚起步，压根没看，密码2也没做出来，需要的脑洞太大了，另外膜飘零师傅。

 

参考：https://www.anquanke.com/post/id/171543