L2-013 红色警报

合集 - 模拟(54)

1.G. Vlad and Trouble at MIT2024-02-202.P2899 [USACO08JAN] Cell Phone Network G2024-02-203.Watering an Array2024-02-234.P2055 [ZJOI2009] 假期的宿舍2024-03-085.T432579 大西洋船王2024-03-086.T432580 星云 hard ver.2024-03-087.P7072 [CSP-J2020] 直播获奖2024-03-098.E - Insert or Erase2024-03-109.D - String Bags2024-03-1010.P2671 [NOIP2015 普及组] 求和2024-03-1011.P1884 [USACO12FEB] Overplanting S2024-03-1012.F. Microcycle2024-03-1213.E. Increasing Subsequences__22024-03-1314.G. Path Prefixes2024-03-1415.F. Rudolf and Imbalance2024-03-1416.P1355 神秘大三角2024-03-2017.[ARC172A] Chocolate2024-03-2518.F. 0, 1, 2, Tree!2024-03-2919.E. Nearly Shortest Repeating Substring2024-03-2920.P1354 房间最短路问题2024-03-2921.P3258 [JLOI2014] 松鼠的新家2024-04-0222.P3052 [USACO12MAR] Cows in a Skyscraper G2024-04-0523.P1337 [JSOI2004] 平衡点 / 吊打XXX2024-04-0724.P3745 [六省联考 2017] 期末考试2024-04-0825.D. Inaccurate Subsequence Search2024-04-0926.E. Long Inversions2024-04-0927.C. Deep Down Below2024-04-0928.C. Rings2024-04-0929.F. Unfair Game2024-04-1030.C. Inversion Graph2024-04-1031.D. Cross Coloring2024-04-1232.D2. Set To Max (Hard Version)2024-04-1233.C. Array Game2024-04-1234.F. Alex's whims2024-04-1235.Queue Sort2024-04-1236.P10252 线性变换2024-04-1637.P10288 [GESP样题 八级] 区间2024-04-1638.P2161 [SHOI2009] 会场预约2024-04-1739.L2-001 紧急救援2024-04-1840.L2-002 链表去重2024-04-18

41.L2-013 红色警报2024-04-18

42.L2-014 列车调度2024-04-1943.L2-022 重排链表2024-04-1944.L2-023 图着色问题2024-04-1945.L2-039 清点代码库2024-04-1946.L2-034 口罩发放2024-04-1947.L3-037 夺宝大赛2024-04-2348.仓库规划2024-04-2349.因子化简2024-04-2350.C. Torn Lucky Ticket2024-04-2751.俄罗斯方块2024-05-1452.F. Cutting Game2024-05-2153.D. Prefix Permutation Sums2024-06-1754.P3304 [SDOI2013] 直径2024-07-15

收起

原题链接

题解

复杂图论题做多了这种题不会做了
直接模拟即可，标记被摧毁的城市，然后遍历所有城市，能一次性搜索到的城市是一个城市群，累积有几个城市群

code

#include<bits/stdc++.h>
using namespace std;
vector<int> G[505];
int vis[505]={0};
int des[505]={0};
void ss(int now)
{
    vis[now]=1;
    for(auto next:G[now]) if(!vis[next]&&!des[next])  ss(next);

}
int main()
{
    int n,m;
    cin>>n>>m;

    for(int i=1;i<=m;i++)
    {
        int x,y;
        cin>>x>>y;
        G[x].push_back(y);
        G[y].push_back(x);
    }

    int cnt=0;
    for(int i=0;i<n;i++)
    {
        if(!vis[i])
        {
            ss(i);
            cnt++;
        }
    }
    int k;
    cin>>k;
    for(int i=1;i<=k;i++)
    {
        memset(vis,0,sizeof vis);
        int now;
        cin>>now;
        des[now]=1;
        int cnt1=0;
        for(int i=0;i<n;i++)
        {
            if(!vis[i]&&!des[i])
            {
                ss(i);
                cnt1++;
            }
        }
        if(cnt1>cnt) printf("Red Alert: City %d is lost!\n",now);
        else printf("City %d is lost.\n",now);
        cnt=cnt1;
    }

    if(k==n)  puts("Game Over.");
    return 0;
}