G. Lights
1.C. Insert and Equalize2.C. Removal of Unattractive Pairs3.D. Jumping Through Segments4.E. Good Triples5.F. Shift and Reverse6.D. Yet Another Monster Fight7.A. Constructive Problems8.C. Game with Multiset9.A. Rating Increase10.B. Swap and Delete11.A. Problemsolving Log12.B. Preparing for the Contest13.C. Quests14.D. Three Activities15.E2. Game with Marbles (Hard Version)16.cf刷题有感17.A. Anonymous Informant18.A. Forked!19.B. Make Almost Equal With Mod20.C. Heavy Intervals21.D. Split Plus K22.A. 202323.B. Two Divisors24.C. Training Before the Olympiad25.D. Mathematical Problem26.F. Greetings27.C. Partitioning the Array28.G. Bicycles29.E. Eat the Chip
30.G. Lights
31.D. Array Repetition32.D. Berserk Monsters33.E. Increasing Subsequences34.D. Very Different Array35.G. Mischievous Shooter36.B. Plus-Minus Split37.B. A Balanced Problemset38.C. Did We Get Everything Covered39.D. Find the Different Ones!40.C. Grouping Increases41.D. Good Trip42.C. Physical Education Lesson43.E. Final Countdown44.D. Divisible Pairs45.G. Vlad and Trouble at MIT46.A. Brick Wall47.B. Minimize Inversions48.C. XOR-distance49.A. Moving Chips50.B. Monsters Attack!51.C. Find B52.D. Slimes53.C. Turtle Fingers: Count the Values of k54.D. Turtle Tenacity: Continual Mods55.D. Vlad and Division56.C. LR-remainders57.D. Lonely Mountain Dungeons太巧妙了!!
关键1:把开着的灯当成黑点看待
关键二:如图
更多细节请看代码
code
#include<bits/stdc++.h>
using namespace std;
int to[100005];//代表会被我影响的灯,抽象成边
void solve()
{
int n;
int state[100005]={0};//代表每个灯的状态
int ind[100005]={0};//代表入度
string s;
cin>>n>>s;
vector<int> ans;//代表答案,需要关掉灯的编号
for(int i=1;i<=n;i++)
{
cin>>to[i];
ind[to[i]]++;
if(s[i-1]=='1')state[i]=1;//用数组代替,方便计算
}
queue<int> q;
for(int i=1;i<=n;i++) if(!ind[i]) q.push(i);//从入度为零的点开始消除,即消除链
while(q.size())
{
int now=q.front();
q.pop();
if(--ind[to[now]]==0)q.push(to[now]);
if(state[now])//把开着的灯想象成黑色的点,开关后,黑点会向下移动,且黑点遇到黑点时会消除
{
ans.push_back(now);
state[to[now]]^=1;
state[now]=0;
}
}
for(int i=1;i<=n;i++)
{
if(ind[i])//现在把链全部去掉了,环可能有多个
{
int x=i,len=0,half=0,curstate=0;
while(ind[x]--)
{
curstate^=state[x];
half+=curstate;
len++;
x=to[x];
}
if(curstate)
{
cout<<"-1"<<endl;//如果环上的黑点奇数个,肯定无法消除
return;
}
for(int i=1;i<=len;i++)//这一段判断环上需要关掉灯的方法太巧妙了!!
{
curstate^=state[x];
if(curstate==(2*half<=len))ans.push_back(x);
x=to[x];
}
}
}
cout<<ans.size()<<endl;
for(int i:ans)cout<<i<<" ";
cout<<endl;
}
int main()
{
ios::sync_with_stdio(false);
int t;
cin>>t;
while(t--) solve();
return 0;
}
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