B. Swap and Delete
1.C. Insert and Equalize2.C. Removal of Unattractive Pairs3.D. Jumping Through Segments4.E. Good Triples5.F. Shift and Reverse6.D. Yet Another Monster Fight7.A. Constructive Problems8.C. Game with Multiset9.A. Rating Increase
10.B. Swap and Delete
11.A. Problemsolving Log12.B. Preparing for the Contest13.C. Quests14.D. Three Activities15.E2. Game with Marbles (Hard Version)16.cf刷题有感17.A. Anonymous Informant18.A. Forked!19.B. Make Almost Equal With Mod20.C. Heavy Intervals21.D. Split Plus K22.A. 202323.B. Two Divisors24.C. Training Before the Olympiad25.D. Mathematical Problem26.F. Greetings27.C. Partitioning the Array28.G. Bicycles29.E. Eat the Chip30.G. Lights31.D. Array Repetition32.D. Berserk Monsters33.E. Increasing Subsequences34.D. Very Different Array35.G. Mischievous Shooter36.B. Plus-Minus Split37.B. A Balanced Problemset38.C. Did We Get Everything Covered39.D. Find the Different Ones!40.C. Grouping Increases41.D. Good Trip42.C. Physical Education Lesson43.E. Final Countdown44.D. Divisible Pairs45.G. Vlad and Trouble at MIT46.A. Brick Wall47.B. Minimize Inversions48.C. XOR-distance49.A. Moving Chips50.B. Monsters Attack!51.C. Find B52.D. Slimes53.C. Turtle Fingers: Count the Values of k54.D. Turtle Tenacity: Continual Mods55.D. Vlad and Division56.C. LR-remainders57.D. Lonely Mountain Dungeons反思 要明确每个变量的含义!!!
读题
1.取一对01置换,或者删掉一个元素,使得经过若干次改变后的序列
一些事实的思考
1.对于一个给定的序列
答案是可以的。具体请参考线性代数中逆序数的介绍,看完你就明白了。
2.截取
思路
1.线性循环,计算当前状态含01的个数,和达到当前状态时减去01的个数,有多少个零->就需要保留多少个1->就需要减去多少个1
2.如果需要1或0的个数不够了,说明达不到当前状态,后面状态也一定达不到,退出。
代码
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin>>n;
while(n--)
{
string s;
cin>>s;
int a=0,b=0;
for(int i=0;s[i];i++)
if(s[i]=='1')a++;
else b++;
int ans=a+b;
int a1=0,b1=0;
for(int i=0;s[i];i++)
{
if(s[i]=='1')b1++;
else a1++;
if(a1>a||b1>b)break;
ans=min(ans,a+b-a1-b1);//总数减去需要保留的个数
}
cout<<ans<<endl;
}
return 0;
}
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