hdu 5726 GCD

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5726

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 #define cl(a,b) memset(a,b,sizeof(a))
 4 #define LL long long
 5 #define pb push_back
 6 #define gcd __gcd
 7 
 8 const int maxn = 1e5+200;
 9 const int inf  = 1 << 23;
10 
11 int n;LL a[maxn];
12 LL node[maxn*4];
13 
14 void push_up(int rt){
15     node[rt] = gcd(node[rt<<1],node[rt<<1|1]);
16 }
17 
18 void build(int rt,int l,int r){
19     if(l==r){
20         node[rt]=a[l];
21         return ;
22     }
23     int mid = l+r>>1;
24     build(rt<<1, l, mid);
25     build(rt<<1|1, mid+1, r);
26     push_up(rt);
27 }
28 
29 LL query(int rt,int l,int r,int x,int y){
30     //printf("rt = %d, l = %d, r = %d, x = %d,y = %d\n",rt,l,r,x,y);
31     if(x<=l&&y>=r){
32         return node[rt];
33     }
34     int mid = l+r>>1;
35     LL lson=0 ,rson=0;
36 
37     if(x<=mid) lson = query(rt<<1,l,mid,x,y);
38     if(y>mid)  rson = query(rt<<1|1,mid+1,r,x,y);
39     if(lson==0)return rson;
40     if(rson==0)return lson;
41     return gcd(lson,rson);
42 }
43 
44 map<LL,LL> f[maxn];//f[i]记录下第a[i]形成的gcd的集合
45 map<LL,LL> ans;
46 
47 int main(){
48     int T;scanf("%d",&T);
49     int cas = 1;
50     while(T--){
51         
52         scanf("%d",&n);
53         for(int i=1;i<=n;i++){
54             scanf("%d",&a[i]);
55         }
56         printf("Case #%d:\n",cas++);
57 
58         build(1,1,n);
59         ans.clear();
60         for(int i=0;i<=n;i++)f[i].clear();
61 
62         ans[a[1]]=1;f[1][a[1]]=1;
63         for(int i=2;i<=n;i++){
64             ans[a[i]]++;f[i][a[i]]+=1;
65             for(map<LL,LL>::iterator it = f[i-1].begin();it!=f[i-1].end();it++){
66                 LL tmp = gcd(a[i],it->first);
67                 f[i][tmp]+=it->second;
68                 ans[tmp]+=it->second;
69             }
70         }
71 
72         int q;scanf("%d",&q);
73         while(q--){
74             int x,y;scanf("%d%d",&x,&y);
75             LL _gcd = query(1,1,n,x,y);
76             printf("%lld %lld\n",_gcd,ans[_gcd]);
77         }
78     }
79     return 0;
80 }

 

posted @ 2016-07-25 21:20  pter  阅读(201)  评论(0)  编辑  收藏  举报