android 解析XML文件方法之一---DOM

DOM的方式主要是通过遍历节点。一步步查找。

<?xml version="1.0" encoding="UTF-8"?>
<persons>
    <person id="1">
        <name>张三</name>
        <age>20</age>
    </person>
    <person id="2">
        <name>李四</name>
        <age>21</age>
    </person>
</persons>

Java代码 

import java.io.InputStream;
import java.util.ArrayList;
import java.util.List;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;

import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;


/**
 * 使用Dom解析xml文件
 *
 */
public class DomXMLReader {

public static List<Person> readXML(InputStream inStream) {
    List<Person> persons = new ArrayList<Person>();
    DocumentBuilderFactory factory =  DocumentBuilderFactory.newInstance();
    try {
        DocumentBuilder builder = factory.newDocumentBuilder();
        Document dom = builder.parse(inStream);
        Element root = dom.getDocumentElement();
        NodeList items = root.getElementsByTagName("person");
        //查找所有person节点
      for (int i = 0; i < items.getLength(); i++) {
          Element personNode = (Element) items.item(i);
                //获取person节点的id属性值
          person.setId(new Integer(personNode.getAttribute("id")));
                //获取person节点下的所有子节点(标签之间的空白节点和name/age元素)
                NodeList childsNodes = personNode.getChildNodes();
                for (int j = 0; j < childsNodes.getLength(); j++) {
                  Node node = (Node) childsNodes.item(j);
                  //判断是否为元素类型
            if(node.getNodeType() == Node.ELEMENT_NODE){
                    Element childNode = (Element) node;
                    //判断是否name元素
              if ("name".equals(childNode.getNodeName())) {
                 //得到name的值
                 String age= cnode.getFirstChild().getNodeValue().toString();
                                          } else if (“age”.equals(childNode.getNodeName())) {
                        String age=childNode.getFirstChild().getNodeValue());
                      }
                   }
                }
            persons.add(person);
        }
        inStream.close();
    } catch (Exception e) {
        e.printStackTrace();
    }
    return persons;
}