随笔分类 -  数论

POJ3090(欧拉函数)
摘要:Visible Lattice Points Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 6681 Accepted: 4000 Description A lattice point (x, y) in the first 阅读全文

posted @ 2016-09-07 15:36 vCoders 阅读(374) 评论(0) 推荐(0) 编辑

POJ2478(欧拉函数)
摘要:Farey Sequence Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 15242 Accepted: 6054 Description The Farey Sequence Fn for any integer n wit 阅读全文

posted @ 2016-09-07 15:07 vCoders 阅读(226) 评论(0) 推荐(0) 编辑

POJ2407(欧拉函数)
摘要:Relatives Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 13693 Accepted: 6834 Description Given n, a positive integer, how many positive i 阅读全文

posted @ 2016-09-07 11:49 vCoders 阅读(328) 评论(0) 推荐(0) 编辑

POJ2142(扩展欧几里得)
摘要:The Balance Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 5991 Accepted: 2605 Description Ms. Iyo Kiffa-Australis has a balance and only 阅读全文

posted @ 2016-09-07 10:54 vCoders 阅读(321) 评论(0) 推荐(0) 编辑

HDU1576(扩展欧几里得)
摘要:A/B Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4252 Accepted Submission(s): 3277 Problem Des 阅读全文

posted @ 2016-07-24 21:00 vCoders 阅读(131) 评论(0) 推荐(0) 编辑

POJ1061(线性同余方程)
摘要:青蛙的约会 Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 105587 Accepted: 20789 Description 两只青蛙在网上相识了,它们聊得很开心,于是觉得很有必要见一面。它们很高兴地发现它们住在同一条纬度线上 阅读全文

posted @ 2016-07-24 17:06 vCoders 阅读(374) 评论(0) 推荐(1) 编辑

HDU1021(模运算)
摘要:Fibonacci Again Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 52548 Accepted Submission(s): 248 阅读全文

posted @ 2016-07-24 14:34 vCoders 阅读(359) 评论(0) 推荐(0) 编辑

POJ3292(素数筛选)
摘要:Semi-prime H-numbers Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 8706 Accepted: 3809 Description This problem is based on an exercise o 阅读全文

posted @ 2016-07-18 19:58 vCoders 阅读(681) 评论(0) 推荐(0) 编辑

POJ3421(质因数分解)
摘要:X-factor Chains Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 6501 Accepted: 2023 Description Given a positive integer X, an X-factor cha 阅读全文

posted @ 2016-07-18 16:25 vCoders 阅读(914) 评论(0) 推荐(0) 编辑

nefu26(求数的位数)
摘要:Description 根据密码学需要,要计算某些数的阶乘的位数. Description Description 根据密码学需要,要计算某些数的阶乘的位数. Input 第一行为整数n ,接下来 n 行, 每行1个数m (1 ≤ m ≤ 10^7) . Input Input 第一行为整数n ,接 阅读全文

posted @ 2016-05-11 18:49 vCoders 阅读(152) 评论(0) 推荐(0) 编辑

HDOJ(1018)
摘要:Big Number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 34743 Accepted Submission(s): 16478 Pr 阅读全文

posted @ 2015-07-30 18:58 vCoders 阅读(226) 评论(0) 推荐(0) 编辑

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