617. Merge Two Binary Trees

https://leetcode.com/problems/merge-two-binary-trees/#/description

 

Given two binary trees and imagine that when you put one of them to cover the other, some nodes of the two trees are overlapped while the others are not.

You need to merge them into a new binary tree. The merge rule is that if two nodes overlap, then sum node values up as the new value of the merged node. Otherwise, the NOT null node will be used as the node of new tree.

Example 1:

Input: 
	Tree 1                     Tree 2                  
          1                         2                             
         / \                       / \                            
        3   2                     1   3                        
       /                           \   \                      
      5                             4   7                  
Output: 
Merged tree:
	     3
	    / \
	   4   5
	  / \   \ 
	 5   4   7

 

Note: The merging process must start from the root nodes of both trees.

 

Sol:

 

 

If two trees are not none, then add values from too trees to be the new root. And the left child of the newroot is written by calling the merTrees function recursively. The inputs are left leaf of the first tree and the left leaf of the second tree. Do this the same to the right leaf of newroot.

 

If one of the trees is none while another is not none, return the existing tree. If both trees are none, return none then. 

 

 

# Definition for a binary tree node.
class TreeNode(object):
    def __init__(self, x):
        self.val = x
        self.left = None
        self.right = None

class Solution(object):
    def mergeTrees(self, t1, t2):
        if t1 and t2:
            root = TreeNode(t1.val + t2.val)
            root.left = self.mergeTrees(t1.left, t2.left)
            root.right = self.mergeTrees(t1.right, t2.right)
            return root
        else:
            return t1 or t2