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https://leetcode.com/problems/count-and-say/#/description

 

The count-and-say sequence is the sequence of integers beginning as follows:
1, 11, 21, 1211, 111221, ...

1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.

Given an integer n, generate the nth sequence.

Note: The sequence of integers will be represented as a string.

 

Sol:

 

class Solution(object):
    def countAndSay(self, n):
        """
        :type n: int
        :rtype: str
        """
        s='1'
        for i in range(n-1):
            count = 1
            temp = []
            for index in range(1,len(s)):
                if s[index] == s[index-1]:
                    count += 1
                else:
                    temp.append(str(count))
                    temp.append(s[index-1])
                    count = 1
            temp.append(str(count))
            temp.append(s[-1])
            s = ''.join(temp)
        return s

 

TWO SOLUTIONS IN:

https://discuss.leetcode.com/topic/28084/simple-python-solution/4

 

.join() in python 

http://www.cnblogs.com/jsplyy/p/5634640.html

 

 

 

posted on 2017-06-06 20:18  Premiumlab  阅读(114)  评论(0编辑  收藏  举报