Rational
1081 Rational Sum
#include <iostream> #include <cstdio> #include <cstdlib> #include <algorithm> #include <string> #include <string.h> #include <vector> #include <cmath> using namespace std; typedef long long ll; int n; ll ca,cb; ll a[110],b[110]; inline ll gcd(ll x,ll y){ x=abs(x),y=abs(y); while(y^=x^=y^=x%=y); return x; } int main() { scanf("%d",&n); for(int i=1;i<=n;++i){ scanf("%lld/%lld",&a[i],&b[i]); int g=gcd(a[i],b[i]); a[i]/=g,b[i]/=g; } ca=a[1],cb=b[1]; for(int i=2;i<=n;++i){ ll gb=gcd(cb,b[i]); ll tb=(cb/gb)*b[i]; ll ta=ca*(tb/cb)+a[i]*(tb/b[i]); if(tb<0){ tb=-tb; ta=-ta; } int g=gcd(ta,tb); ca=ta/g,cb=tb/g; } if(ca<0){ printf("-"); ca=-ca; } if(ca%cb==0) printf("%lld\n",ca/cb); else{ if(ca/cb) printf("%lld ",ca/cb); printf("%lld/%lld\n",ca%cb,cb); } return 0; }
1088 Rational Arithmetic
#include <iostream> #include <cstdio> #include <cstdlib> #include <algorithm> #include <string> #include <string.h> #include <vector> using namespace std; typedef long long ll; string op[4]={"+","-","*","/"}; string s1,s2; ll pos,n1,d1,n2,d2; inline ll gcd(ll a,ll b) { while(b^=a^=b^=a%=b); return a; } void prllNumber(ll n,ll d){ if(n==0) cout<<"0"; else{ ll f=1; if((n<0&&d>0)||(n>0&&d<0)){ f=-1; n=abs(n),d=abs(d); } ll g=gcd(n,d); n/=g,d/=g; if(f<0) cout<<"(-"; if(n%d==0) cout<<n/d; else{ if(n>d) cout<<n/d<<" "<<n%d; else cout<<n; cout<<"/"<<d; } if(f<0) cout<<")"; } } void prllLine(ll opIdx){ prllNumber(n1,d1); cout<<" "<<op[opIdx]<<" "; prllNumber(n2,d2); cout<<" = "; ll n3,d3; if(op[opIdx]=="+"){ n3=n1*d2+n2*d1,d3=d1*d2; }else if(op[opIdx]=="-"){ n3=n1*d2-n2*d1,d3=d1*d2; }else if(op[opIdx]=="*"){ n3=n1*n2,d3=d1*d2; }else{ if(n2==0){cout<<"Inf"<<endl;return;} n3=n1*d2,d3=d1*n2; } prllNumber(n3,d3); cout<<endl; } int main() { cin>>s1>>s2; pos=s1.find("/"); n1=stoi(s1.substr(0,pos)); d1=stoi(s1.substr(pos+1)); pos=s2.find("/"); n2=stoi(s2.substr(0,pos)); d2=stoi(s2.substr(pos+1)); prllLine(0); prllLine(1); prllLine(2); prllLine(3); return 0; }
本文作者:Ryomk
本文链接:https://www.cnblogs.com/preccrep/p/16456285.html
版权声明:本作品采用知识共享署名-非商业性使用-禁止演绎 2.5 中国大陆许可协议进行许可。
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