现有数据为: 200001 1000 200002 1100 200003 1200 200004 1300 200005 1400 200006 1500 200007 1600 200101 1100 200202 1200 200301 1300 想要转化为以下结构的数据: year char(4) --年份 month1 number(10,2) --1月销售金额 month2 number(10,2) --2月销售金额 month3 number(10,2) --3月销售金额 month4 number(10,2) --4月销售金额 month5 number(10,2) --5月销售金额 month6 number(10,2) --6月销售金额 month7 number(10,2) --7月销售金额 month8 number(10,2) --8月销售金额 month9 number(10,2) --9月销售金额 month10 number(10,2) --10月销售金额 month11 number(10,2) --11月销售金额 month12 number(10,2) --12月销售金额 结构转化的SQL语句为: create or replace view v_sale(year,month1,month2,month3,month4,month5,month6,month7,month8,month9,month10,month11,month12) as select substrb(month,1,4), sum(decode(substrb(month,5,2),'01',sell,0)), sum(decode(substrb(month,5,2),'02',sell,0)), sum(decode(substrb(month,5,2),'03',sell,0)), sum(decode(substrb(month,5,2),'04',sell,0)), sum(decode(substrb(month,5,2),'05',sell,0)), sum(decode(substrb(month,5,2),'06',sell,0)), sum(decode(substrb(month,5,2),'07',sell,0)), sum(decode(substrb(month,5,2),'08',sell,0)), sum(decode(substrb(month,5,2),'09',sell,0)), sum(decode(substrb(month,5,2),'10',sell,0)), sum(decode(substrb(month,5,2),'11',sell,0)), sum(decode(substrb(month,5,2),'12',sell,0)) from sale group by substrb(month,1,4); |
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