MySQL数据库SQL语法常规操作
必备sql和表关系及授权
graph LR
执行1[必备sql和授权]
执行2[SQL强化和实践]
执行3[索引和函数以及存储过程]
执行4[Python操作mysql和应用]
执行5[常见SQL语句]
执行6[表关系]
执行7[授权管理]
执行8[一对多]
执行9[多对多]
Mysql --> 执行1
Mysql --> 执行2
Mysql --> 执行3
Mysql --> 执行4
执行1 --> 执行5
执行1 --> 执行6
执行1 --> 执行7
执行6 --> 执行8
执行6 --> 执行9
简要:
- 必备SQL(八个必备)
- 表关系
- 授权
1.必备SQL语句
通过下面这两张表进行SQL语句延申测试
depart表跟info表
create database test default charset utf8 collate utf8_general_ci;
在test数据库创建两个需要关联的表
use test;
create table depart (
id int not null auto_increment primary key,
title varchar(16) not null
)default charset utf8;
create table info (
id int not null auto_increment key,
name varchar(16) not null,
email varbinary(32) not null,
age int,
depart_id int
);
插入数据
use test;
insert into depart(title) value ("开发"),("运营"),("销售");
insert into info(name,email,age,depart_id) value("吴佩琦","wupeiqi@live.com",19,1);
insert into info(name,email,age,depart_id) value("张三","zhangsan@live.com",49,1);
insert into info(name,email,age,depart_id) value("李氏","lishi@live.com",9,2);
insert into info(name,email,age,depart_id) value("王五","wangwu@live.com",29,1);
insert into info(name,email,age,depart_id) value("李杰","lijie@live.com",39,3);
insert into info(name,email,age,depart_id) value("超","cao@live.com",49,1);
insert into info(name,email,age,depart_id) value("关羽","guanyu@live.com",49,1);
1.1.条件
根据条件搜索结果
select * from info where id > 1;
select * from info where id = 1;
select * from info where id >= 1;
select * from info where id != 1;
select * from info where id between 2 and 4; -- id 大于2且小于4
select * from info where name = "张三" and age = "49";
select * from info where name = "张三" or age = "49";
select * from info where (name = "张三" or email = "zhangsan@live.com") and age = "49";
select * from info where id in (1,4,6); -- 多个取值
select * from info where name in ('吴佩琦','王五','超'); -- 或者这样除数字外条件需要单引号
select * from info where id in (select id from depart); -- 联合查询info表的id字段跟depart表的所有id字段匹配
select * from info where exists (select * from depart where id = 5); -- exists判断相当于if,如果depart表有id=5的字段成立进行查询,如果depart表有id=5的字段不成立不进行查询
select * from info where not exists (select * from depart where id = 5); -- exists判断相当于取反
-- 不直接查莫一张表,先通过SQL查询到这张表的数据然后再做筛选
select * from (select * from info where id > 5) as T where T.age > 10; -- as T 这个T相当于括号里面查询出来后重新定义出来的临时表
select * from info where info.id > 5; -- where 条件的时候用表名加字段,一般用于多表联合查询时区分info.id
1.2.通配符
如果数据量小可以使用下面的通配符方法的sql进行查询,如果数据量大一般需要工具进行查询,如使用es
select * from info where name like "%王%"; -- %取任意长度的任意字符
select * from info where name like "王%"; -- 匹配后面任意长度的任意字符,如果%在前面的任意字符就不存在
select * from info where name like "%佩琦";
select * from info where name like "吴%琦";
select * from info where email like "__peiqi@live.com"; -- 一个下划线代表一个字符
select * from info where email like "__peiqi_live.com";
1.3.映射
-- max/min/sum
-- 注意少用select * 这种方法在程序里面去查数据,根据需求几列获取几列
select
id,
name,
666 as num, -- 添加一个字段数据,并定义字段名为num
(select max(id) from depart) as mid, -- 定义depart表的id最大值为mid字段数据
(select min(id) from depart) as nid, -- 定义depart表的id最小值为nid字段数据
(select sum(id) from depart) as sid, -- 定义depart表的id的和为sid字段数据
age
from info;
-- 下面这两种查询方式效率比较低程序用的比较少
select
id,
name,
(select title from depart where depart.id=info.depart_id) as x1
from info;
select
id,
name,
(select title from depart where depart.id=info.depart_id) as x1,
(select title from depart where depart.id=info.id) as x2
from info;
-- case when then else的使用方法,相当于if,then(如果成立就是什么)
select
id,
name,
case depart_id when 1 then "第一部门" end v1
from info;
select
id,
name,
case depart_id when 1 then "第一部门" end v1,
case depart_id when 1 then "第一部门" else "其它" end v2,
case depart_id when 1 then "第一部门" when 2 then "第二部门" else "其它" end v3,
case when age < 18 then "少年" end v4,
case when age < 18 then "少年" else "油腻男" end v5,
case when age < 18 then "少年" when age < 39 then "青年" else "油腻男" end v6
from info;
1.4.排序
-- order by (先查询再进行排序)
select * from info order by age desc; -- 倒序排列
select * from info order by age asc; -- 顺序排列(默认顺序)
select * from info order by age asc,id desc; -- 有限安装age进行从小到大,如果age相同则按照id从大到小
select * from info where id > 5 order by age asc,id desc; -- 添加个筛选条件在进行排序
select * from info where id > 10 or info.email like '%guan%' order by age asc,id desc;
1.5.取部分
select * from info limit 5; -- 取前五行
select * from info order by id desc limit 3; -- 先排序再取前三行
select * from info where id >5 order by id desc limit 3;
select * from info limit 3 offset 2; -- 从位置2开始,向后获取前3条
1.6.分组
-- group by
select age,max(id),min(id),sum(id) from info group by age;