洛谷 P3366 【模板】最小生成树
[TOC]
###题目
戳
###思路
最小生成树
$\text\(和\)\text$
###\(Code\)
####\(\text{Prim}\)
/*
Prim+链式前向星
*/
#include<bits/stdc++.h>
#define MAXN 5001
#define inf 1061109567
using namespace std;
int n,m,cnt,ans;
int dis[MAXN],head[MAXN];
bool vis[MAXN];
struct Edge{
int next,to,w;
}edge[200001<<1];
inline int read(){
int x=0;bool f=0;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=!f;c=getchar();}
while(c>='0'&&c<='9'){x=x*10+c-'0';c=getchar();}
return f?-x:x;
}
inline void addedge(int from,int to,int w){
edge[++cnt].to=to,edge[cnt].next=head[from];
edge[cnt].w=w,head[from]=cnt;
}
void Prim(){
int tot=0,k=1;
dis[1]=0;
for(int i=head[1];i;i=edge[i].next){
if(dis[edge[i].to]>edge[i].w)
dis[edge[i].to]=edge[i].w;
}
while(++tot<n){
int sum=0x7fffffff;
vis[k]=1;
for(int i=1;i<=n;++i){
if(!vis[i]&&dis[i]<sum){
k=i;
sum=dis[i];
}
}
ans+=sum;
for(int i=head[k];i;i=edge[i].next){
if(!vis[edge[i].to]&&dis[edge[i].to]>edge[i].w)
dis[edge[i].to]=edge[i].w;
}
}
}
int main(){
memset(dis,0x3f3f3f,sizeof(dis));
n=read(),m=read();
int u,v,w;
while(m--){
u=read(),v=read(),w=read();
addedge(u,v,w),addedge(v,u,w);
}
Prim();
for(int i=1;i<=n;++i){
if(dis[i]==inf){
printf("orz\n");
return 0;
}
}
printf("%d\n",ans);
return 0;
}
/*
Prim+邻接矩阵
*/
#include<iostream>
#include<cstring>
#include<string>
#include<cstdio>
#include<algorithm>
#define MAXN 5001
#define inf 1061109567
using namespace std;
int n,m,ans;
int map[MAXN][MAXN],dis[MAXN];
bool vis[MAXN];
inline int read(){
int x=0;bool f=0;char c=getchar();
while(c<'0'||c>'9'){if(c=='-')f=!f;c=getchar();}
while(c>='0'&&c<='9'){x=x*10+c-'0';c=getchar();}
return f?-x:x;
}
void Prim(){
dis[1]=0;
for(int i=1;i<=n;++i){
int k=0;
for(int j=1;j<=n;++j){
if(!vis[j]&&dis[k]>dis[j]) k=j;
}
vis[k]=1;
for(int j=1;j<=n;++j){
if(!vis[j]&&map[k][j]<dis[j])
dis[j]=map[k][j];
}
}
}
int main(){
memset(map,0x3f3f3f,sizeof(map));
memset(dis,0x3f3f3f,sizeof(dis));
n=read(),m=read();
int u,v,w;
for(int i=1;i<=m;++i){
u=read(),v=read(),w=read();
if(map[u][v]>w){
map[u][v]=w;
map[v][u]=w;
}
}
Prim();
for(int i=1;i<=n;++i){
ans+=dis[i];
if(dis[i]==inf){
printf("orz\n");
return 0;
}
}
printf("%d\n",ans);
return 0;
}