摘要: 1:#status.odd 是否奇数行2:#status.count 当前行数3:#status.index 当前行的序号,从0开始『#status.count=#status.index+1』4:#status.first 是否第一行5:#status.last 是否最后一行6:#status.m... 阅读全文
posted @ 2011-09-16 19:03 Pocter 阅读(378) 评论(0) 推荐(0) 编辑
摘要: function getYestoday(date){ var yesterday_milliseconds=date.getTime()-1000*60*60*24; var yesterday = new Date(); yesterday.setTime(y... 阅读全文
posted @ 2011-09-16 13:04 Pocter 阅读(1028) 评论(0) 推荐(0) 编辑