445 C. Petya and Catacombs

http://codeforces.com/contest/890/problem/C

A very brave explorer Petya once decided to explore Paris catacombs. Since Petya is not really experienced, his exploration is just walking through the catacombs.

Catacombs consist of several rooms and bidirectional passages between some pairs of them. Some passages can connect a room to itself and since the passages are built on different depths they do not intersect each other. Every minute Petya arbitrary chooses a passage from the room he is currently in and then reaches the room on the other end of the passage in exactly one minute. When he enters a room at minute i, he makes a note in his logbook with number ti:

  • If Petya has visited this room before, he writes down the minute he was in this room last time;
  • Otherwise, Petya writes down an arbitrary non-negative integer strictly less than current minute i.

Initially, Petya was in one of the rooms at minute 0, he didn't write down number t0.

At some point during his wandering Petya got tired, threw out his logbook and went home. Vasya found his logbook and now he is curious: what is the minimum possible number of rooms in Paris catacombs according to Petya's logbook?

Input

The first line contains a single integer n (1 ≤ n ≤ 2·105) — then number of notes in Petya's logbook.

The second line contains n non-negative integers t1, t2, ..., tn (0 ≤ ti < i) — notes in the logbook.

Output

In the only line print a single integer — the minimum possible number of rooms in Paris catacombs.

Examples
input
Copy
2
0 0
output
2
input
Copy
5
0 1 0 1 3
output
3
Note

In the first sample, sequence of rooms Petya visited could be, for example 1 → 1 → 2, 1 → 2 → 1 or 1 → 2 → 3. The minimum possible number of rooms is 2.

In the second sample, the sequence could be 1 → 2 → 3 → 1 → 2 → 1.

 

 

// 去吧!皮卡丘! 把AC带回来!
//      へ     /|
//   /\7    ∠_/
//   / │   / /
//  │ Z _,< /   /`ヽ
//  │     ヽ   /  〉
//  Y     `  /  /
//  イ● 、 ●  ⊂⊃〈  /
//  ()  へ    | \〈
//   >ー 、_  ィ  │ //
//   / へ   / ノ<| \\
//   ヽ_ノ  (_/  │//
//    7       |/
//    >―r ̄ ̄`ー―_
//**************************************
#pragma comment(linker, "/STACK:1024000000,1024000000")
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define inf 2147483647
const ll INF = 0x3f3f3f3f3f3f3f3fll;
#define ri register int
template <class T> inline T min(T a, T b, T c) { return min(min(a, b), c); }
template <class T> inline T max(T a, T b, T c) { return max(max(a, b), c); }
template <class T> inline T min(T a, T b, T c, T d) {
  return min(min(a, b), min(c, d));
}
template <class T> inline T max(T a, T b, T c, T d) {
  return max(max(a, b), max(c, d));
}
#define scanf1(x) scanf("%d", &x)
#define scanf2(x, y) scanf("%d%d", &x, &y)
#define scanf3(x, y, z) scanf("%d%d%d", &x, &y, &z)
#define scanf4(x, y, z, X) scanf("%d%d%d%d", &x, &y, &z, &X)
#define pi acos(-1)
#define me(x, y) memset(x, y, sizeof(x));
#define For(i, a, b) for (int i = a; i <= b; i++)
#define FFor(i, a, b) for (int i = a; i >= b; i--)
#define bug printf("***********\n");
#define mp make_pair
#define pb push_back
const int maxn = 2e5 + 10;
// name*******************************
int n;
int a[maxn];
int ans = 1;
bool flag[maxn];
// function******************************

//***************************************
int main() {
  // ios::sync_with_stdio(0); cin.tie(0);
  // freopen("test.txt", "r", stdin);
  //  freopen("outout.txt","w",stdout);
  cin >> n;
  flag[0] = 1;
  For(i, 1, n) {
    cin >> a[i];
    if (flag[a[i]]) {
      flag[a[i]] = 0;
      flag[i] = 1;
    } else {
      flag[i] = 1;
      ans++;
    }
  }
  cout << ans;

  return 0;
}
View Code

 

 

posted @ 2018-03-12 12:59  planche  阅读(187)  评论(0编辑  收藏  举报