摘要： A Simple Chess Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 614 Accepted Submission(s): 159 Pr 阅读全文

摘要： Two Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 163 Accepted Submission(s): 72 Problem Descri 阅读全文

摘要： Divide the Sequence Time Limit: 5000/2500 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 119 Accepted Submission(s): 7 阅读全文

摘要： #include #include #include using namespace std; int main() { string s,line; while(getline(cin,line)&&line[0]!='#') { stringstream ss(line); set dict; while(ss>>s... 阅读全文

摘要： void ex_gcd(ll a,ll b,ll &d,ll &x,ll &y){ if(!b){d=a;x=1LL;y=0LL;} else {ex_gcd(b,a%b,d,y,x);y-=x*(a/b);} }/////大数乘法取模转换成加法取模，避免爆long long ll mult(ll a,ll k,ll m){ ll res=0; while(k... 阅读全文

摘要： Lucky7 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 933 Accepted Submission(s): 345 Problem De 阅读全文

摘要： 拓展欧几里得： 当 gcd （ a ， b ）= d 时，求绝对值和最小的 x ， y 使得 x * a + y * b = d ； d = gcd （ a ， b ） = gcd （ b ， a mod b ）； 设： x1 * a + y1 * b = d ； ① x2 * b + y2 * （ 阅读全文

摘要： 解析：http://blog.sina.com.cn/s/blog_b9a401a40101dghn.html 阅读全文

摘要： Another Meaning Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 526 Accepted Submission(s): 245 P 阅读全文

摘要： Bubble Sort Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 106 Accepted Submission(s): 76 Proble 阅读全文