leetcode 226. Invert Binary Tree
Invert a binary tree.
4 / \ 2 7 / \ / \ 1 3 6 9
to
4 / \ 7 2 / \ / \ 9 6 3 1
.
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode* invertTree(TreeNode* root) { if (root == nullptr) return nullptr; swap(root->left, root->right); root->left = invertTree(root->left); root->right = invertTree(root->right); return root; } };
原文地址:http://www.cnblogs.com/pk28/
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