leetcode 268. Missing Number
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n
, find the one that is missing from the array.
For example,
Given nums = [0, 1, 3]
return 2
.
Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?
呵呵
class Solution { public: int missingNumber(vector<int>& nums) { int sum = 0; for (int x : nums) { sum += x; } int n = nums.size(); return n * (1 + n) / 2 - sum; } };
原文地址:http://www.cnblogs.com/pk28/
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