HDU_2057——64位无符号16进制数的运算

Problem Description

There must be many A + B problems in our HDOJ , now a new one is coming. Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too. Easy ? AC it !

 

 

Input

The input contains several test cases, please process to the end of the file. Each case consists of two hexadecimal integers A and B in a line seperated by a blank. The length of A and B is less than 15.

 

 

Output

For each test case,print the sum of A and B in hexadecimal in one line.

 

 

Sample Input

+A -A +1A 12 1A -9 -1A -12 1A -AA

 

 

Sample Output

0 2C 11 -2C -90

#include <cstdio>
int main()
{
   __int64 a,b,c;
   //十六进制数直接可以运算，字母X要大写 
   while(~scanf("%I64X%I64X",&a,&b))
      {
         //输入的时候是10...10101010
         //存储的时候是11...01010110补码形式 
         //输出的时候是FF...56
         //如果和的符号位是-的话，先-1再取反就变回原码形式 
         //然后再另外输出一个'-' 
         c=a+b;
         if(c<0)
            printf("-%I64X\n",~(c-1));
         else
            printf("%I64X\n",c);
      }
   return 0;
}