HDU_2055——刷题不要使用fflush()
Problem Description
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26; Give you a letter x and a number y , you should output the result of y+f(x).
Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.
Output
for each case, you should the result of y+f(x) on a line.
Sample Input
6 R 1 P 2 G 3 r 1 p 2 g 3
Sample Output
19 18 10 -17 -14 -4
1 #include <cstdio> 2 int main() 3 { 4 int T, n; 5 char ch; 6 scanf("%d",&T); 7 while(T--) 8 { 9 //fflush(stdin);//切记不能使用这个.. 10 getchar(); 11 scanf("%c %d",&ch,&n); 12 if(ch>='a'&&ch<='z') 13 { 14 printf("%d\n",n+(96-ch)); 15 } 16 else 17 { 18 printf("%d\n",n+(ch-64)); 19 } 20 } 21 return 0; 22 }
——现在的努力是为了小时候吹过的牛B!!