贴一段shell代码
好久没用shell了,呵呵,这个是当counter < 1000的时候,往tmp.sql里填这两个字符串,生成假数据。
#!/usr/bin/env bash COUNTER=1 while [ $COUNTER -lt 1000 ]; do echo The counter is $COUNTER cat<<EOF >>tmp.sql INSERT INTO "wcdata" VALUES('`(printf "%03d" $COUNTER)`','0.00','0.00','0.00183','85.47943','4773267.7216','-10669.18'); EOF echo The counter is $COUNTER cat<<EOF >>tmp.sql INSERT INTO "wcxx" VALUES('`(printf "%03d" $COUNTER)`','同步输出','模拟小电压,0.5V','模拟小电压,0.5V','','2015-01-23-19-52-36'); EOF let COUNTER=COUNTER+1 done
另一个,在rcS中调用这个脚本,每次开机去检查/home/plg,删除image目录,并删除/pcap中旧的文件(只保留最新的6个)。
#!/bin/sh counter=0 app_path=/home/plg if [ -e $app_path/pcap ] ;then file_list=`ls -ct $app_path/pcap/*.pcap` for file in $file_list; do counter=`expr $counter + 1` if [ $counter -gt 6 ] ;then echo "Remove old file, rm file $file" rm -rf $file fi done fi if [ -e $app_path/image ] ;then echo "Remove the image dir!" rm -rf $app_path/image fi
上面的代码当“$app_path/pcap”中的文件名有空格,程序会出错,所以,对它进行了改进
if [ -e $app_path/pcap ] ;then ls -ct $app_path/pcap/*.pcap | while read file; do counter=`expr $counter + 1` if [ $counter -gt 6 ] ;then echo "Remove old file, rm file $file" rm -rf "$file" fi done fi
——————无论在哪里做什么,只要坚持服务、创新、创造价值,其他的东西自然都会来的。