摘要: assume cs:code code segment mov bx,020H mov ds,bx mov bx,0 mov cx,63 s:mov [bx],bx inc bx loop s mov ax,4c00H int 21H code ends end 阅读全文
posted @ 2020-11-14 19:29 phpwyl 阅读(1850) 评论(0) 推荐(1) 编辑