【Python】递归获取嵌套json 的所有key及value值

 代码

class recurPostDict:
    """ 递归获取多维嵌套字典所有层级的key和value """

    def __init__(self, datas):
        self.datas = datas

    def recur_data(self, data: dict, result=""):
        """多维/嵌套字典数据无限遍历,获取所有key层和value"""
        # 使用isinstance检测数据类型:字典类型
        if isinstance(data, dict):
            for k, v in data.items():
                if result == "":
                    self.recur_data(v, k)
                else:
                    self.recur_data(v, result+"_%s" % str(k))
        # 列表或元组类型
        elif isinstance(data, (list, tuple)):
            if len(data) == 1:
                for i in range(len(data)):
                    # 自我调用实现无限遍历,单个不加修饰
                    self.recur_data(data[i], result)
            else:
                for i in range(len(data)):
                    # 自我调用实现无限遍历,多个增加字母修饰
                    self.recur_data(data[i], result+"_%s" % public_tools.forward("a", i))
        else:
            # print(result + "=" + str(data))
            self.datas[result] = str(data)

 

 

运行:

if __name__ == "__main__":
    dic = {"name": "zhangsan", "address": {"sheng": "beijing", "shiji": "beijing", "shiqu": ["shijingshan", "p"], "qu": {"1dong": "1", "2dong": "2"}}}
    t = recurPostDict({})  # 传入空字典{},即datas初始值为{}
    t.recur_data(dic, result="")  # 执行过程
    print(t.datas)
    print(t.datas.keys())
    print(t.datas.values())

 

 执行结果

 

 

 

 

public_tools.forward() 字母表循环迭代实现地址:https://www.cnblogs.com/phoenixy/p/17126439.html

 

def params_to_line(content: str):
    col_name = []
    col_value = []
    for key, value in up_colname.items():
        if type(value) == list:
            if len(value) == 0:
                pass
            elif len(value) == 1:
                for sub_key, sub_value in value[0].items():
                    sub_key = key + "_" + sub_key
                    col_name.append(sub_key)
                    col_value.append(sub_value)
            else:
                for i in range(len(value)):
                    for sub_key, sub_value in value[i].items():
                        sub_key = key + "_" + sub_key + "_" + public_tools.forward("a", 5)
                        col_name.append(sub_key)
                        col_value.append(sub_value)
        else:
            logs.warning(f"解析参数时, 出现字符串、字典、列表以外的{type(value)}类型,无法将{key}对应的字段落库 ~")      
初版

 

posted @ 2023-02-16 14:01  Phoenixy  阅读(693)  评论(0编辑  收藏  举报