Python源码学习(六)-PyCodeObject初探

demo1.py

 

def f():
	c=1
	print("Hello")

a=9
b=5	
f();


co.py

 

 

source = open('demo1.py').read()
co = compile(source, 'demo1.py', 'exec')
print("type:")
print(type(co))
print("dir(co)")
print(dir(co))
print("co.co_name:" + co.co_name)
print("co.co_names:")
for i in co.co_names:
	print(i)
print("-" * 30)

print("co.co_code:")
print(co.co_code)
print("-" * 30)

print("co.co_consts:")
for i in co.co_consts:
	print(i)
print("-" * 30)

print("co.co_filename:")
print(co.co_filename)
print("-" * 30)

print("co.nlocals:")
print(co.co_nlocals)
print("-" * 30)

print("co.co_stacksize:")
print(co.co_stacksize)
print("co.co_lnotab;")
print(co.co_lnotab)

print("-" * 30)
print("co.co_varnames:")
for i in co.co_varnames:
	print(i)


结果

 

 

type:
<class 'code'>
dir(co):
['__class__', '__delattr__', '__doc__', '__eq__', '__format__', '__ge__', '__getattribute__', '__gt__', '__hash__', '__init__', '__le__', '__lt__', '__ne__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__', 'co_argcount', 'co_cellvars', 'co_code', 'co_consts', 'co_filename', 'co_firstlineno', 'co_flags', 'co_freevars', 'co_kwonlyargcount', 'co_lnotab', 'co_name', 'co_names', 'co_nlocals', 'co_stacksize', 'co_varnames']
co.co_name:<module>
co.co_names:
f
a
b
------------------------------
co.co_code:
b'd\x00\x00\x84\x00\x00Z\x00\x00d\x01\x00Z\x01\x00d\x02\x00Z\x02\x00e\x00\x00\x83\x00\x00\x01d\x03\x00S'
------------------------------
co.co_consts:
<code object f at 0x00C0D2F0, file "demo1.py", line 1>
9
5
None
------------------------------
co.co_filename:
demo1.py
------------------------------
co.nlocals:
0
------------------------------
co.co_stacksize:
1
co.co_lnotab;
b'\t\x04\x06\x01\x06\x01'
------------------------------
co.co_varnames:


 

 

posted on 2013-10-11 15:46  云编程的梦  阅读(265)  评论(0编辑  收藏  举报

导航