HDU1272 小希的迷宫

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1272
#include<iostream>
using namespace std;

const int MAX_VETEX_NUM = 100001;
bool flag[MAX_VETEX_NUM];
int connectedList[MAX_VETEX_NUM];
bool isOk = true;
int nStart,nEnd;

void initConnectedList()
{
    
for (int i = 0; i < MAX_VETEX_NUM; ++i)
    {    
        connectedList[i] 
= i;
        flag[i] 
= false;
    }
}
int findInConnectList(int vetex)
{
    
int pos = vetex;
    
while(pos != connectedList[pos])
       {
        pos 
= connectedList[pos];
    }
    
return pos;
}
int countListNum()
{
    
int count = 0;
    
for (int i = 0; i < MAX_VETEX_NUM; ++i)
    {
        
if (flag[i] == true)
        {
            
if (findInConnectList(i) == i)
            {
                
++count;
            }
        }
    }
    
return count;
}

void process()
{
    
if( findInConnectList(nStart) == findInConnectList(nEnd))
    {
           isOk 
= false;
           
return;
    }
    
if( findInConnectList(nStart) == nStart && findInConnectList(nEnd) == nEnd)
       {
        connectedList[nEnd] 
= nStart;
    }    
    
else if(findInConnectList(nStart) == nStart)
       {
        connectedList[nStart] 
= findInConnectList(nEnd);
    }
    
else 
       {
        connectedList[nEnd] 
= findInConnectList(nStart);
    }
    flag[nStart] 
= true;
    flag[nEnd] 
= true;
}
int main()
{
    
while(cin >> nStart >> nEnd)
    {
           
if(nStart == -1 && nEnd == -1break;
           
if(nStart || nEnd)
           {
            isOk 
= true;
            memset(flag, 
false ,sizeof(flag));
            initConnectedList();
            process();
            
while(cin >> nStart >> nEnd,nStart || nEnd)
            {
               
if(isOk == true 
               {
                   process();
               }
               }
            
if(isOk == true// 如果没有回环,也有可能在不同连通分量中
            {
                
int count = 0
                count 
= countListNum();
                 
if(count>1)
                  {
                    isOk 
= false;
                }
            }
           }
           
else
           {
            isOk 
= true;
           }
           
if(isOk == false)
        {
            cout 
<< "No" << endl;
        }
           
else
        {
            cout 
<< "Yes" << endl;
        }
    }
    
return 0;
}

posted on 2009-09-15 18:51  Phinecos(洞庭散人)  阅读(1985)  评论(1编辑  收藏  举报

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