摘要: Problem Description A simple mathematical formula for e is where n is allowed to go to infinity. This can actually yield very accurate approximations 阅读全文
posted @ 2011-04-27 21:51 pcoda 阅读(291) 评论(0) 推荐(0) 编辑
摘要: 输出下列图形16 210 7 313 11 8415 14 129 5#includeint main(){int i,j,a[100][100],n,k;while(scanf("%d",&n)!=EOF){k=1;for(i=1;i<=n;i++){for(j=1;j<=n+1-i;j++){a[i-1+j][j]=k;k++;}}... 阅读全文
posted @ 2011-04-27 18:52 pcoda 阅读(153) 评论(0) 推荐(0) 编辑
摘要: 北京大学http://acm.pku.edu.cn/JudgeOnline/(推荐)浙江大学http://acm.zju.edu.cn/(推荐)北京邮电大学http://acm.cs.bupt.cn/onlinejudge/天津大学http://acm.tju.edu.cn/toj/四川大学http://acm.scu.edu.cn/soj/中科大http://acm.ustc... 阅读全文
posted @ 2011-04-27 18:40 pcoda 阅读(525) 评论(0) 推荐(0) 编辑