Topcoder711B

Problem Statement

    

You are given the Strings s and t. Both strings have the same length.

 

You are allowed to modify s. In each step you may choose two valid indices i and j such that i > j, and change s[i] to s[j]. For example, if s = "abc", you may choose i=2 and j=0, which will change s to "aba".

 

Return "Possible" (quotes for clarity) if you can change s into t by a sequence of zero or more steps. Otherwise, return "Impossible".

Note that the return values are case-sensitive.

Definition

    
Class: StringTransform
Method: isPossible
Parameters: String, String
Returns: String
Method signature: String isPossible(String s, String t)
(be sure your method is public)

Limits

    
Time limit (s): 2.000
Memory limit (MB): 512
Stack limit (MB): 512

Constraints

- s will contain between 1 and 1,000 characters, inclusive.
- s and t will be of equal length.
- s will contain only lowercase English letters.
- t will contain only lowercase English letters.

Examples

0)  
    
"abc"
"aba"
Returns: "Possible"
This is the example from the problem statement. We can change s into t by changing s[2] to s[0].
1)  
    
"abc"
"bbc"
Returns: "Impossible"
Note that in each step i must be greater than j. You are not allowed to choose i=0 and j=1.
2)  
    
"topcoder"
"topcoder"
Returns: "Possible"
The two strings are equal, so we don't have to make any changes.
3)  
    
"rdmcxnnbbe"
"rdrrxrnxbe"
Returns: "Possible"
 
4)  
    
"rdmcxnnbbe"
"rdqrxrnxbe"
Returns: "Impossible"
import java.util.*;
public class StringTransform {
   
    public static String isPossible(String s,String t){
        Set<Character> set = new HashSet<Character>();
      set.clear();
        for(int i=0;i<s.length();++i) {
           
            if (s.charAt(i) != t.charAt(i)) {
                if (!set.contains(t.charAt(i)))
                    return "Impossible";
            }
                set.add(s.charAt(i));
                
            }
        
        return "Possible";

    }
}

  

posted @ 2018-03-14 16:11  xianbeigg  阅读(94)  评论(0编辑  收藏  举报