CF1420E Battle Lemmings

CF1420E Battle Lemmings

大菜鸡参考了两位哥哥的博客才写出来的

zqy1018

夕林山寸

//Proudly using c++11 by gwt 
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int,int> pii;
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define fi first
#define se second
#define all(x) (x).begin(),(x).end()
//#define endl '\n'
#define count2(x) __builtin_popcount(x)
#define countleadingzero(x) __builtin_clz(x)
#define debug(x) cerr << #x << " = " << x << endl;
inline ll read(){//not solve LLONG_MIN LMAX=9,223,372,036,854,775,807
    ll s=0,w=1;char ch=getchar();
    while(ch<'0'||ch>'9'){if(ch=='-')w=-1;ch=getchar();}
    while(ch>='0' && ch<='9')s=s*10+ch-'0',ch=getchar();
    return s*w;
}
int dp[81][81][81*41];
// i\j\k i in pos j cost k
// show the minnimize numbers of part i "0..0"
int main(){
	int n;
	cin>>n;
	vector<int>nums(n+1);
	int tot1=0; 
	vector<int>pos1;
	for(int i=1;i<=n;++i){
		cin>>nums[i];
		if(nums[i]==1)pos1.pb(i);
	}
	int sum=0;
	tot1=pos1.size();
	sum+=n*(n-1)/2;//every pair of n;
	sum-=tot1*(tot1-1)/2;//every pair of 11
	sum-=tot1*(n-tot1);//every pair of 10/01
	int cost=0;
	memset(dp,0x3f,sizeof(dp));
	dp[0][0][0]=0;
	for(int i=0;i<pos1.size();++i){
		if(i==0)
		cost+=max(0,(pos1[i]-1)*(pos1[i]-2)/2);
		else
		cost+=max(0,(pos1[i]-pos1[i-1]-1)*(pos1[i]-pos1[i-1]-2)/2);
		dp[i+1][pos1[i]][0]=cost;
		//cout<<cost<<'\n';
	}
	int i=0;
	const int MAXM=n*(n-1)/2;
	for(auto posi:pos1){
		i++;
		for(int j=1;j<=n;++j){
			for(int t=0;t<j;++t){
				for(int k=0;k<=MAXM;++k){
					int &PT=dp[i][j][abs(j-posi)+k];
					PT=min(PT,dp[i-1][t][k]+max(0,(j-t-1)*(j-t-2)/2));
				}
			}
		}
//		cout<<cnt1<<' '<<tot1<<'\n';
	}
	int ans=1e9;
	for(int k=0;k<=MAXM;++k){
		for(int j=1;j<=n;++j){
			//sum-pastito
//			cout<<dp[tot1][j][k]<<" ";
			ans=min(ans,dp[tot1][j][k]+max(0,(n-j)*(n-j-1)/2));
//			cout<<ans<<'\n';
		}
//		cout<<endl;
		if(tot1==0)
		sum=ans;
		cout<<sum-ans<<" \n"[k==MAXM];
	}
//	ios::sync_with_stdio(0),cin.tie(0),cout.tie(0);
	return 0;
}