部门工资最高的员工 前3高的员工

 

部门工资最高的员工 - LeetCode (中国) https://leetcode-cn.com/problems/department-highest-salary/description/


SELECT d11.Department AS Department,e11.Name AS Employee,d11.maxSalary AS Salary FROM (

SELECT MAX(Salary) AS maxSalary,d1.Name AS Department,d1.Id AS maxId FROM Employee e1 LEFT JOIN Department d1 ON e1.DepartmentId = d1.Id WHERE d1.Name IS NOT NULL GROUP BY d1.Name
) AS d11 LEFT JOIN Employee e11 ON d11.maxSalary=e11.Salary AND d11.maxId=e11.DepartmentId

ORDER BY Salary ASC

 

Employee 表包含所有员工信息,每个员工有其对应的 Id, salary 和 department Id 。

+----+-------+--------+--------------+
| Id | Name  | Salary | DepartmentId |
+----+-------+--------+--------------+
| 1  | Joe   | 70000  | 1            |
| 2  | Henry | 80000  | 2            |
| 3  | Sam   | 60000  | 2            |
| 4  | Max   | 90000  | 1            |
| 5  | Janet | 69000  | 1            |
| 6  | Randy | 85000  | 1            |
+----+-------+--------+--------------+

Department 表包含公司所有部门的信息。

+----+----------+
| Id | Name     |
+----+----------+
| 1  | IT       |
| 2  | Sales    |
+----+----------+

编写一个 SQL 查询,找出每个部门工资前三高的员工。例如,根据上述给定的表格,查询结果应返回:

+------------+----------+--------+
| Department | Employee | Salary |
+------------+----------+--------+
| IT         | Max      | 90000  |
| IT         | Randy    | 85000  |
| IT         | Joe      | 70000  |
| Sales      | Henry    | 80000  |
| Sales      | Sam      | 60000  |
+------------+----------+--------+

 

 

SELECT D.Name AS Department,E.Name AS Employee,E.Salary AS Salary
FROM Employee AS E
INNER JOIN Department AS D
ON D.Id = E.DepartmentId
WHERE (
SELECT COUNT(DISTINCT Salary)
FROM Employee AS P4
WHERE E.DepartmentId = P4.DepartmentId
AND P4.Salary >= E.Salary
) <= 3
ORDER BY DepartmentId,Salary DESC



 

posted @ 2018-05-28 13:13  papering  阅读(329)  评论(0编辑  收藏  举报