摘要:
# 交集aa={'qwe','asd','zxc'}cc={'uio','qwe'}aa_and_cc=[]for i in aa: if i in cc: aa_and_cc.append(i)print(aa_and_cc)aa={'qwe','asd','zxc'}cc={'uio','qwe',}print(aa.intersection(cc))print(aa&c... 阅读全文
posted @ 2019-03-27 19:59 攀一座山 阅读(274) 评论(0) 推荐(0) 编辑