223. Rectangle Area

Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

Assume that the total area is never beyond the maximum possible value of int.

 链接: http://leetcode.com/problems/rectangle-area/

7/20/2017

一开始看错题目了,以为求overlap部分的面积。其实需要球所有面积

要先计算是否有重叠,再来按照公式算重叠部分面积,否则没有重叠的话会有错。

 1 public class Solution {
 2     public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
 3         int overlap = 0;
 4         if (C < E || G < A || D < F || H < B) {
 5             overlap = 0;
 6         } else {
 7             overlap = (Math.min(C, G) - Math.max(A, E)) * (Math.min(D, H) - Math.max(B, F));
 8         }
 9         return (C - A) * (D - B) + (G - E) * (H - F) - overlap;
10     }
11 }

别人的算法

https://discuss.leetcode.com/topic/17705/just-another-short-way

更多讨论

https://discuss.leetcode.com/category/231/rectangle-area

posted @ 2017-07-20 19:34  panini  阅读(205)  评论(0编辑  收藏  举报