205. Isomorphic Strings

题目:

Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,
Given "egg""add", return true.

Given "foo""bar", return false.

Given "paper""title", return true.

Note:
You may assume both s and t have the same length.

链接:  http://leetcode.com/problems/isomorphic-strings/

2/24/2017

需要用2个hashmap,aa - > ab是不成立的

 1 public class Solution {
 2     public boolean isIsomorphic(String s, String t) {
 3         if (s.length() != t.length()) return false;
 4 
 5         HashMap<Character, Character> h1 = new HashMap<Character, Character>();
 6         HashMap<Character, Character> h2 = new HashMap<Character, Character>();
 7         char a, b;
 8 
 9         for (int i = 0; i < s.length(); i++) {
10             a = s.charAt(i);
11             b = t.charAt(i);
12             if (h1.containsKey(a)) {
13                 if (h1.get(a) != b) return false;
14                 h1.put(a, b);
15             } else {
16                 h1.put(a, b);
17             }
18             if (h2.containsKey(b)) {
19                 if (h2.get(b) != a) return false;
20             } else {
21                 h2.put(b, a);
22             }
23         }
24         return true;
25 
26     }
27 }

别人的好算法可以用bitmap,留给二刷。

posted @ 2017-02-25 03:05  panini  阅读(118)  评论(0编辑  收藏  举报