24. Swap Nodes in Pairs

题目:

Given a linked list, swap every two adjacent nodes and return its head.

For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.

Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.

链接: http://leetcode.com/problems/swap-nodes-in-pairs/

一刷

class Solution(object):
    def swapPairs(self, head):
        """
        :type head: ListNode
        :rtype: ListNode
        """
        dummy_node = ListNode(0)
        dummy_node.next = head
        prev = dummy_node
        cur = head
while cur and cur.next: prev.next = cur.next cur.next = cur.next.next prev.next.next = cur
prev
= cur cur = cur.next return dummy_node.next

二刷需要加上recursion解法

posted @ 2016-06-08 11:07  panini  阅读(110)  评论(0编辑  收藏  举报