Hackinglab之脚本关

1.key又找不到了。

抓包重放，在返回包中：

2.快速计算。

Payload：

 1 import requests
 2 import re
 3 
 4 url='http://lab1.xseclab.com/xss2_0d557e6d2a4ac08b749b61473a075be1/index.php'
 5 
 6 s= requests.Session()
 7 r=s.get(url)
 8 r.encoding='utf-8'
 9 print(r.text)
10 num=re.findall(re.compile(r'<br/>\s+(.*?)='),r.text)[0]
11 result=eval(num)
12 r=s.post(url,data={'v': eval(num)})
13 print (r.text)

3.这个题目是空的

Payload：

null

4.怎么就是不弹出key呢？

查看源代码，F12运行下面这段代码

var b=function(p,a,c,k,e,r){e=function(c){return(c<a?'':e(parseInt(c/a)))+((c=c%a)>35?String.fromCharCode(c+29):c.toString(36))};if(!''.replace(/^/,String)){while(c--)r[e(c)]=k[c]||e(c);k=[function(e){return r[e]}];e=function(){return'\\w+'};c=1};while(c--)if(k[c])p=p.replace(new RegExp('\\b'+e(c)+'\\b','g'),k[c]);return p}('1s(1e(p,a,c,k,e,r){e=1e(c){1d(c<a?\'\':e(1p(c/a)))+((c=c%a)>1q?1f.1j(c+1k):c.1n(1o))};1g(!\'\'.1h(/^/,1f)){1i(c--)r[e(c)]=k[c]||e(c);k=[1e(e){1d r[e]}];e=1e(){1d\'\\\\w+\'};c=1};1i(c--)1g(k[c])p=p.1h(1l 1m(\'\\\\b\'+e(c)+\'\\\\b\',\'g\'),k[c]);1d p}(\'Y(R(p,a,c,k,e,r){e=R(c){S(c<a?\\\'\\\':e(18(c/a)))+((c=c%a)>17?T.16(c+15):c.12(13))};U(!\\\'\\\'.V(/^/,T)){W(c--)r[e(c)]=k[c]||e(c);k=[R(e){S r[e]}];e=R(){S\\\'\\\\\\\\w+\\\'};c=1};W(c--)U(k[c])p=p.V(Z 11(\\\'\\\\\\\\b\\\'+e(c)+\\\'\\\\\\\\b\\\',\\\'g\\\'),k[c]);S p}(\\\'G(B(p,a,c,k,e,r){e=B(c){A c.L(a)};E(!\\\\\\\'\\\\\\\'.C(/^/,F)){D(c--)r[e(c)]=k[c]||e(c);k=[B(e){A r[e]}];e=B(){A\\\\\\\'\\\\\\\\\\\\\\\\w+\\\\\\\'};c=1};D(c--)E(k[c])p=p.C(I J(\\\\\\\'\\\\\\\\\\\\\\\\b\\\\\\\'+e(c)+\\\\\\\'\\\\\\\\\\\\\\\\b\\\\\\\',\\\\\\\'g\\\\\\\'),k[c]);A p}(\\\\\\\'t(h(p,a,c,k,e,r){e=o;n(!\\\\\\\\\\\\\\\'\\\\\\\\\\\\\\\'.m(/^/,o)){l(c--)r[c]=k[c]||c;k=[h(e){f r[e]}];e=h(){f\\\\\\\\\\\\\\\'\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\w+\\\\\\\\\\\\\\\'};c=1};l(c--)n(k[c])p=p.m(q s(\\\\\\\\\\\\\\\'\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\b\\\\\\\\\\\\\\\'+e(c)+\\\\\\\\\\\\\\\'\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\b\\\\\\\\\\\\\\\',\\\\\\\\\\\\\\\'g\\\\\\\\\\\\\\\'),k[c]);f p}(\\\\\\\\\\\\\\\'1 3="6";1 4="7";1 5="";8(1 2=0;2<9;2++){5+=3+4}\\\\\\\\\\\\\\\',j,j,\\\\\\\\\\\\\\\'|u|i|b|c|d|v|x|y|j\\\\\\\\\\\\\\\'.z(\\\\\\\\\\\\\\\'|\\\\\\\\\\\\\\\'),0,{}))\\\\\\\',H,H,\\\\\\\'|||||||||||||||A||B||M||D|C|E|F||I||J|G|N|O||P|Q|K\\\\\\\'.K(\\\\\\\'|\\\\\\\'),0,{}))\\\',X,X,\\\'||||||||||||||||||||||||||||||||||||S|R|V|W|U|T|Y|13|Z|11|14|12|10|19|1a|1b|1c\\\'.14(\\\'|\\\'),0,{}))\',1t,1u,\'|||||||||||||||||||||||||||||||||||||||||||||||||||||1e|1d|1f|1g|1h|1i|1v|1s|1l||1m|1n|1o|1r|1k|1j|1q|1p|1w|1x|1y|1z\'.1r(\'|\'),0,{}))',62,98,'|||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||return|function|String|if|replace|while|fromCharCode|29|new|RegExp|toString|36|parseInt|35|split|eval|62|75|53|var|slakfj|teslkjsdflk|for'.split('|'),0,{});
               var d=eval(b);
               alert("key is first 14 chars"+d);

利用python 截取。去掉chars

a='charsslakfjteslkjsdflkslakfjteslkjsdflkslakfjteslkjsdflkslakfjteslkjsdflkslakfjteslkjsdflkslakfjteslkjsdflkslakfjteslkjsdflkslakfjteslkjsdflkslakfjteslkjsdflkslakfjteslkjsdflk'
print (len(a))  //判断长度
print (a[5:19])    //截取

5.逗比验证码第一期

4位密码，暴力破解。