SRM 588 D2 L2：GUMIAndSongsDiv2，冷静思考，好的算法简洁明了

题目来源：http://community.topcoder.com/stat?c=problem_statement&pm=12707

算法决定一切，这道题目有很多方法解，个人认为这里 vexorian 给出的解法最简便，编码也最容易。而使用brute force 和 DP都比较复杂。

代码如下：

 

#include <algorithm>
#include <iostream>
#include <sstream>

#include <string>
#include <vector>
#include <stack>
#include <deque>
#include <queue>
#include <set>
#include <map>

#include <cstdio>
#include <cstdlib>
#include <cctype>
#include <cmath>
#include <cstring>

using namespace std;


/*************** Program Begin **********************/

class GUMIAndSongsDiv2 {
public:
    int maxSongs(vector <int> duration, vector <int> tone, int T) {
	int res = 0;
	int N = duration.size();

	vector <int> songs;
	for (int i = 0; i < N; i++) {
		for (int j = i; j < N; j++) {
			int maxTone = max(tone[i], tone[j]);
			int minTone = min(tone[i], tone[j]);
			songs.clear();
			for (int k = 0; k < N; k++) {
				if (tone[k] <= maxTone && tone[k] >= minTone) {
					songs.push_back(duration[k]);
				}
			}
			sort(songs.begin(), songs.end());
			int sum = 0;
			int c = 0;
			for (int k = 0; k < songs.size(); k++) {
				sum += songs[k];
				if (sum <= T - maxTone + minTone) {
					++c;
				}
			}
			res = max(res, c);
		}
	}

	return res;
    }
};

/************** Program End ************************/