ZUC-S盒输入输出测试

问题

实现以二进制、十进制、十六进制的形式输入，经过S盒，输出十六进制

输入：

1、二进制：10001010010011110000011110111101

2、十进制：2320435133

3、十六进制：8a4f07bd

输出：3c873379

S盒介绍

32位4个小的8*8的盒并置而成，即${\rm{S = }}({S_0},{S_1},{S_2},{S_3})$,其中${S_0}{\rm{ = }}{S_2},{S_1}{\rm{ = }}{S_3}$

程序

#define _CRT_SECURE_NO_DEPRECATE
#include <stdio.h>
#include <stdlib.h> 
#include <time.h>
#include <string.h>
#include <math.h>

typedef unsigned char u8;//0~255
typedef unsigned int u32;//

u32 input, tmp,output;

/* the s-boxes  S盒*/
u8 S0[256] = {
0x3e,0x72,0x5b,0x47,0xca,0xe0,0x00,0x33,0x04,0xd1,0x54,0x98,0x09,0xb9,0x6d,0xcb,
0x7b,0x1b,0xf9,0x32,0xaf,0x9d,0x6a,0xa5,0xb8,0x2d,0xfc,0x1d,0x08,0x53,0x03,0x90,
0x4d,0x4e,0x84,0x99,0xe4,0xce,0xd9,0x91,0xdd,0xb6,0x85,0x48,0x8b,0x29,0x6e,0xac,
0xcd,0xc1,0xf8,0x1e,0x73,0x43,0x69,0xc6,0xb5,0xbd,0xfd,0x39,0x63,0x20,0xd4,0x38,
0x76,0x7d,0xb2,0xa7,0xcf,0xed,0x57,0xc5,0xf3,0x2c,0xbb,0x14,0x21,0x06,0x55,0x9b,
0xe3,0xef,0x5e,0x31,0x4f,0x7f,0x5a,0xa4,0x0d,0x82,0x51,0x49,0x5f,0xba,0x58,0x1c,
0x4a,0x16,0xd5,0x17,0xa8,0x92,0x24,0x1f,0x8c,0xff,0xd8,0xae,0x2e,0x01,0xd3,0xad,
0x3b,0x4b,0xda,0x46,0xeb,0xc9,0xde,0x9a,0x8f,0x87,0xd7,0x3a,0x80,0x6f,0x2f,0xc8,
0xb1,0xb4,0x37,0xf7,0x0a,0x22,0x13,0x28,0x7c,0xcc,0x3c,0x89,0xc7,0xc3,0x96,0x56,
0x07,0xbf,0x7e,0xf0,0x0b,0x2b,0x97,0x52,0x35,0x41,0x79,0x61,0xa6,0x4c,0x10,0xfe,
0xbc,0x26,0x95,0x88,0x8a,0xb0,0xa3,0xfb,0xc0,0x18,0x94,0xf2,0xe1,0xe5,0xe9,0x5d,
0xd0,0xdc,0x11,0x66,0x64,0x5c,0xec,0x59,0x42,0x75,0x12,0xf5,0x74,0x9c,0xaa,0x23,
0x0e,0x86,0xab,0xbe,0x2a,0x02,0xe7,0x67,0xe6,0x44,0xa2,0x6c,0xc2,0x93,0x9f,0xf1,
0xf6,0xfa,0x36,0xd2,0x50,0x68,0x9e,0x62,0x71,0x15,0x3d,0xd6,0x40,0xc4,0xe2,0x0f,
0x8e,0x83,0x77,0x6b,0x25,0x05,0x3f,0x0c,0x30,0xea,0x70,0xb7,0xa1,0xe8,0xa9,0x65,
0x8d,0x27,0x1a,0xdb,0x81,0xb3,0xa0,0xf4,0x45,0x7a,0x19,0xdf,0xee,0x78,0x34,0x60
};

u8 S1[256] = {
0x55,0xc2,0x63,0x71,0x3b,0xc8,0x47,0x86,0x9f,0x3c,0xda,0x5b,0x29,0xaa,0xfd,0x77,
0x8c,0xc5,0x94,0x0c,0xa6,0x1a,0x13,0x00,0xe3,0xa8,0x16,0x72,0x40,0xf9,0xf8,0x42,
0x44,0x26,0x68,0x96,0x81,0xd9,0x45,0x3e,0x10,0x76,0xc6,0xa7,0x8b,0x39,0x43,0xe1,
0x3a,0xb5,0x56,0x2a,0xc0,0x6d,0xb3,0x05,0x22,0x66,0xbf,0xdc,0x0b,0xfa,0x62,0x48,
0xdd,0x20,0x11,0x06,0x36,0xc9,0xc1,0xcf,0xf6,0x27,0x52,0xbb,0x69,0xf5,0xd4,0x87,
0x7f,0x84,0x4c,0xd2,0x9c,0x57,0xa4,0xbc,0x4f,0x9a,0xdf,0xfe,0xd6,0x8d,0x7a,0xeb,
0x2b,0x53,0xd8,0x5c,0xa1,0x14,0x17,0xfb,0x23,0xd5,0x7d,0x30,0x67,0x73,0x08,0x09,
0xee,0xb7,0x70,0x3f,0x61,0xb2,0x19,0x8e,0x4e,0xe5,0x4b,0x93,0x8f,0x5d,0xdb,0xa9,
0xad,0xf1,0xae,0x2e,0xcb,0x0d,0xfc,0xf4,0x2d,0x46,0x6e,0x1d,0x97,0xe8,0xd1,0xe9,
0x4d,0x37,0xa5,0x75,0x5e,0x83,0x9e,0xab,0x82,0x9d,0xb9,0x1c,0xe0,0xcd,0x49,0x89,
0x01,0xb6,0xbd,0x58,0x24,0xa2,0x5f,0x38,0x78,0x99,0x15,0x90,0x50,0xb8,0x95,0xe4,
0xd0,0x91,0xc7,0xce,0xed,0x0f,0xb4,0x6f,0xa0,0xcc,0xf0,0x02,0x4a,0x79,0xc3,0xde,
0xa3,0xef,0xea,0x51,0xe6,0x6b,0x18,0xec,0x1b,0x2c,0x80,0xf7,0x74,0xe7,0xff,0x21,
0x5a,0x6a,0x54,0x1e,0x41,0x31,0x92,0x35,0xc4,0x33,0x07,0x0a,0xba,0x7e,0x0e,0x34,
0x88,0xb1,0x98,0x7c,0xf3,0x3d,0x60,0x6c,0x7b,0xca,0xd3,0x1f,0x32,0x65,0x04,0x28,
0x64,0xbe,0x85,0x9b,0x2f,0x59,0x8a,0xd7,0xb0,0x25,0xac,0xaf,0x12,0x03,0xe2,0xf2
};

#define MAKEU32(a, b, c, d) (((u32)(a) << 24) | ((u32)(b) << 16)| ((u32)(c) << 8) | ((u32)(d)))//将取出的4个8位数值连接在一起
/* F */
u32 ISD_ZUC_F(u32 u)
{
	tmp = MAKEU32(S0[u >> 24], S1[(u >> 16) & 0xFF], S0[(u >> 8) & 0xFF], S1[u & 0xFF]);//作用是分别取出每两位。例：8a4f07bd ，分别取出8a、4f、07、bd
	return tmp;
}

/*输出函数*/
u32 OUTPUT()
{
	output = ISD_ZUC_F(input);
	printf("\n输出：%x\n--------------------\n", output);
	return 0;
}

int main()
{
	int num;
	printf("-------------- - S盒测试-------------- -\n");
	printf("请输入一个32位的数，请选择：\n1、二进制\n2、十进制\n3、十六进制\n");
	scanf("%d",&num);
	if (num == 1)
	{
		u8 a[33];
		printf("--------------------\n请输入二进制的数（例：10001010010011110000011110111101）：");
		u32 sum = 0;
		scanf("%s",a);  //输入的是字符串
		//二进制转十进制
		for (int i = 0; i < 32; i++)
		{
			sum = sum * 2 + (a[i] - '0'); //'0'对应的ASCII码值与'1'对应的ASCII码值相差为1,通过ch-'0'可以直接算出int型的值1或者0
		}
		input = sum;
		OUTPUT();
	}
	else if (num == 2)
	{
		printf("--------------------\n请输入十进制的数（例：2320435133）：");
		scanf("%d", &input);
		OUTPUT();
	}
	else if (num == 3)
	{
		printf("--------------------\n请输入十六进制的数（例：8a4f07bd）：");
		scanf("%x", &input);
		OUTPUT();
	}else
	{
		printf("请输入正确的选项！\n");
	}
	return 0;
}