闰年判断

闰年判断

(1)闰年定义:1.除100余数非0且除4余0

            2.除400余数为0

 

(2)流程图:

 

 

代码1:(c语言)

#include <stdio.h>

int main()
{
  int year = 2000;
  while (year <= 2500)
  {
    if (year % 100 != 0 && year % 4 == 0 || year % 400 == 0)
    {
      printf("YES");
    }
    else
    {
      printf("NO");
    }
    year++;
  }
}

  return 0;
}

代码2:(python)

year=2000
while year<=2500:
  if year%100!=0 and year%4==0:
    print('YES')
  elif year%400==0:
    print('YES')
  else:
    print('NO')
  year=year+1

posted @ 2019-03-10 09:37  王祉  阅读(1075)  评论(0编辑  收藏  举报