【转】Is there anyway to create null terminated string in Go

 

 

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Is there anyway to create null terminated string in Go?

What I'm currently trying is a:="golang\0" but it is showing compilation error:

non-octal character in escape sequence: "

stringgoc-strings

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edited Jun 24 '16 at 8:29

icza

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asked Jun 24 '16 at 6:57

Yash Srivastava

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  If you need it, use 0 insted to get your work done. – ameyCU Jun 24 '16 at 7:03 
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  See: golang.org/ref/spec#String_literals . – Volker Jun 24 '16 at 7:42
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  NUL is escaped as \x00 in strings. Also, the language doesn't provide NUL-terminated strings so.. yes, you are forced to modify every string. – toqueteos Jun 24 '16 at 8:05

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Spec: String literals:

The text between the quotes forms the value of the literal, with backslash escapes interpreted as they are in rune literals (except that \' is illegal and \" is legal), with the same restrictions. The three-digit octal (\nnn) and two-digit hexadecimal (\xnn) escapes represent individual bytes of the resulting string; all other escapes represent the (possibly multi-byte) UTF-8 encoding of individual characters.

So \0 is an illegal sequence, you have to use 3 octal digits:

s := "golang\000"

Or use hex code (2 hex digits):

s := "golang\x00"

Or a unicode sequence (4 hex digits):

s := "golang\u0000"

Example:

s := "golang\000"
fmt.Println([]byte(s))
s = "golang\x00"
fmt.Println([]byte(s))
s = "golang\u0000"
fmt.Println([]byte(s))

Output: all end with a 0-code byte (try it on the Go Playground).

[103 111 108 97 110 103 0]
[103 111 108 97 110 103 0]
[103 111 108 97 110 103 0]