Children’s Queue

Children’s Queue

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 10040    Accepted Submission(s): 3198

Problem Description

There are many students in PHT School. One day, the headmaster whose name is PigHeader wanted all students stand in a line. He prescribed that girl can not be in single. In other words, either no girl in the queue or more than one girl stands side by side. The case n=4 (n is the number of children) is like
FFFF, FFFM, MFFF, FFMM, MFFM, MMFF, MMMM
Here F stands for a girl and M stands for a boy. The total number of queue satisfied the headmaster’s needs is 7. Can you make a program to find the total number of queue with n children?

 

Input

There are multiple cases in this problem and ended by the EOF. In each case, there is only one integer n means the number of children (1<=n<=1000)

 

Output

For each test case, there is only one integer means the number of queue satisfied the headmaster’s needs.

 

Sample Input

1
2
3

 

Sample Output

1
2
4
#include<iostream>
#include<iomanip>
using namespace std;
int main()
{
	int n;
	int f[1001][101] = {0};
	f[0][1]=1;
	f[1][1]=1;
	f[2][1]=2;
	f[3][1]=4;
	for(int i=4; i<1001; ++i)
	{
		for(int j=1;j<101;++j)
		{
			f[i][j]+=f[i-1][j]+f[i-2][j]+f[i-4][j];
			f[i][j+1]+=f[i][j]/10000;	
			f[i][j]%=10000;	
		}
	}
	
	while(cin>>n)
	{int j=100;
	while(!f[n][j])
	{j--;}	
	cout<<f[n][j];
	j--;
	for(;j>0;j--)
		printf("%04d", f[n][j]);
	cout<<endl;

	
	}
	
	return 0;
}