树的孩子链表表示法

import tree.PTree.PTNode;

//树的孩子链表表示法
public class CTree<AnyType>{
    
	 int max=100;
	 int n,root,parent,child;
	 PLNode<AnyType> rootNode;
	 CTNode<AnyType> firstChild;
	 PLNode nodes[]=new PLNode[max];
	 
	class CTNode<AnyType>{              //孩子结点
		int Child;
		CTNode<AnyType> nextChild;
		public CTNode(int child){
			this.Child=child;
			nextChild=null;
		}
	}
	class PLNode<AnyType>{          //双亲结点
		AnyType data;
		CTNode<AnyType> firstChild;
		public PLNode(AnyType data){
			this.data=data;
			firstChild=null;
		}
	}
	
	public CTree(){
		rootNode=null;
		n=0;
	}
	public boolean isEmpty(){
		return n==0;
	} 
	public int childCount(int idx){            //孩子个数
	 	if(nodes[idx].firstChild==null){
	 		return 0;
	 	}
	 	int count=1;
	 	CTNode p=nodes[idx].firstChild;
	 	while(p.nextChild!=null){
	 		p=p.nextChild;
	 		count++;
	 	}
	 	return count;
	}
	public CTNode getChild(int n,int idx){        //获取第idx个孩子
        if(childCount(n)<idx){
        	return null;
        }
		CTNode p=nodes[n].firstChild;
		for(int i=1;i<idx;i++){
			p=p.nextChild;
			
		}
		return p;
	}
	 public PLNode assign(AnyType data){       //生成一个双亲结点
	   	    PLNode newNode=new PLNode(data);
	   	    return newNode;
	    }
	  public CTNode ass(int child){
		  CTNode newChild=new CTNode(child);
		  return newChild;
	  }
	public void insert(AnyType data,int parent){             //添加
		if(parent==-1){                //根节点
			rootNode=new PLNode(data);
			nodes[0]=rootNode;
			n++;
		}
		else{
			nodes[n]=assign(data);
			CTNode newChild=new CTNode(n);
	        if(childCount(parent)==0){                   
	        	nodes[parent].firstChild=newChild;
	        }  
	        getChild(parent,childCount(parent)).nextChild=newChild;
	        n++;
		}
	}
	
	
	
	
	public static void main(String[] args) {


	}

}

posted @ 2013-11-03 15:51  IT专业户  阅读(1045)  评论(0编辑  收藏  举报