【Android进阶】Android调用WebService的实现

最近想自己搞搞服务器,就从最简单的webservice开始吧

先上效果图


项目结构



开始贴代码,注释都有,有问题的请留言

MainActivity.java

package com.example.webservice;

import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;

import android.app.Activity;
import android.os.Bundle;
import android.os.Handler;
import android.os.Message;
import android.view.View;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;
/**
 * WebService调用实例
 * @author 	ZhaoKaiQiang
 *			
 *			Time:2014年3月11日
 */
public class MainActivity extends Activity {

	private String result;
	private EditText x;
	private EditText y;
	private TextView tv;

	Handler handler = new Handler() {
		public void handleMessage(Message msg) {
			tv.setText(result);
		};
	};

	@Override
	protected void onCreate(Bundle savedInstanceState) {
		super.onCreate(savedInstanceState);
		setContentView(R.layout.activity_main);
		x = (EditText) findViewById(R.id.x);
		y = (EditText) findViewById(R.id.y);
		tv = (TextView) findViewById(R.id.tv);
	}

	public void click(View view) {
		new Thread(new Runnable() {

			@Override
			public void run() {
				//获取返回值
				result = get("Add",
						Integer.valueOf(x.getText().toString().trim()),
						Integer.valueOf(y.getText().toString().trim()));
				//发送message将结果更新
				handler.sendEmptyMessage(1);
			}
		}).start();
	}
	
	/**
	 * 调用WebService
	 * @param Method	方法名
	 * @param x			加数x
	 * @param y			加数y
	 * @return			相加后的结果
	 */
	public  String get(String Method, int x, int y) {
		//命名空间
		String NAME_SPACE = "http://tempuri.org/";
		//Webservice的调用地址url
		String WEBSERVICE_URL = "http://119.167.225.206:55555/WebService1.asmx";
		String data = "0";
		try {
			String soapAction = NAME_SPACE + Method;
			SoapObject request = new SoapObject(NAME_SPACE, Method);
			// 添加方法需要的参数
			request.addProperty("x", x);
			request.addProperty("y", y);
			SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
					SoapEnvelope.VER11);
			envelope.dotNet = true;
			envelope.bodyOut = request;
			HttpTransportSE ht = new HttpTransportSE(WEBSERVICE_URL);
			ht.call(soapAction, envelope);
			if (envelope.getResponse() != null) {
				Object response = (Object) envelope.getResponse();
				//data就是服务器返回的数据
				data = response.toString().trim();
			}
		} catch (Exception e) {
			Toast.makeText(MainActivity.this,e.getMessage(), 0).show();
		}
		return data;
	}

}



activity_main.xml

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical" >

    <TextView
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:text="X"
        android:textSize="22sp" />

    <EditText
        android:id="@+id/x"
        android:layout_width="match_parent"
        android:layout_height="wrap_content" />

    <TextView
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:text="Y"
        android:textSize="22sp" />

    <EditText
        android:id="@+id/y"
        android:layout_width="match_parent"
        android:layout_height="wrap_content" />

    <Button
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:onClick="click"
        android:text="调用WebService" />

    <TextView
        android:id="@+id/tv"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:textSize="22sp" />

</LinearLayout>

最后注意权限,加上上网权限

代码里的服务器是暂时的,可能会失效,把里面的属性换成自己的就可以,有问题,请留言


posted @ 2014-03-11 13:16  IT专业户  阅读(206)  评论(0编辑  收藏  举报