287. Find the Duplicate Number
1. Question:
287. Find the Duplicate Number
https://leetcode.com/problems/find-the-duplicate-number/
Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one.
Example 1:
Input: [1,3,4,2,2]
Output: 2
Example 2:
Input: [3,1,3,4,2] Output: 3
Note:
- You must not modify the array (assume the array is read only).
- You must use only constant, O(1) extra space.
- Your runtime complexity should be less than O(n2).
- There is only one duplicate number in the array, but it could be repeated more than once.
2. Solution:
class Solution: def findDuplicate(self, nums): """ :type nums: List[int] :rtype: int """ tmp = sorted(nums) bf = tmp[0] for each in tmp[1:]: if each == bf: return each bf = each return re
3. Complexity Analysis
Time Complexity : O(Nlog(N))
Space Complexity: O(N)
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