(原創) 如何将秒数转换成day?hour?min?...(localtime()) (C/C++) (C)
.NET Framework的DateTime型别本身就有转Day,Hour,Minute等Method,所以要转十分方便。但C/C++呢?
C/C++的<time.h>(<ctime>)提供了localtime(),可将sec一次转成所要的信息,该struct定义如下
1struct tm {
2 int tm_sec; // sec.
3 int tm_min; // min.
4 int tm_hour; // hour
5 int tm_mday; // day
6 int tm_mon; // month
7 int tm_year; // year
8 int tm_wday; // day of week
9 int tm_yday; // day of year
10 int tm_isdst; // 夏令时间
11}
2 int tm_sec; // sec.
3 int tm_min; // min.
4 int tm_hour; // hour
5 int tm_mday; // day
6 int tm_mon; // month
7 int tm_year; // year
8 int tm_wday; // day of week
9 int tm_yday; // day of year
10 int tm_isdst; // 夏令时间
11}
以下为localtime()的范例程序
1/*
2(C) OOMusou 2006 http://oomusou.cnblogs.com
3
4Filename : localtime.cpp
5Compiler : Visual C++ 8.0
6Description : Demo how to use localtime() to get min part & hour part
7Release : 11/26/2006
8*/
9#include <iostream>
10#include <ctime>
11
12// Time-wasting function
13void foo();
14// Get specified floating point number from double
15int getDigitFromDouble(double, int);
16
17int main() {
18 clock_t t1 = clock();
19 // Time-wasting function
20 foo();
21 clock_t t2 = clock();
22
23 // Total sec., but including floating part, not only integer
24 double sec = (double)(t2 - t1) / CLOCKS_PER_SEC;
25 // 0.1 sec. part
26 int ssec = getDigitFromDouble(sec,1);
27 // Convert dobule to const time_t,
28 // Since localtime needs (const time_t*) parameter
29 const time_t time_t_sec = (time_t)sec;
30 // localtime() return (struct *tm)
31 struct tm* ts = localtime(&time_t_sec);
32
33 std::cout << "Total sec:" << sec << std::endl;
34 std::cout << "min:" << ts->tm_min << std::endl;
35 std::cout << "sec:" << ts->tm_sec << std::endl;
36 std::cout << "0.1 sec:" << ssec << std::endl;
37
38 return 0;
39}
40
41void foo() {
42 for(int i = 0; i != 1000000; ++i)
43 for(int j = 0; j != 100000; ++j);
44}
45
46// get specified floating point number from double
47int getDigitFromDouble(double d, int n) {
48 int t = 1;
49 for(int j = 0; j != n-1; ++j) {
50 t *= 10;
51 }
52
53 d = d * t;
54 int i = (int)d;
55
56 return (int)((double)(d-i)*10);
57}
2(C) OOMusou 2006 http://oomusou.cnblogs.com
3
4Filename : localtime.cpp
5Compiler : Visual C++ 8.0
6Description : Demo how to use localtime() to get min part & hour part
7Release : 11/26/2006
8*/
9#include <iostream>
10#include <ctime>
11
12// Time-wasting function
13void foo();
14// Get specified floating point number from double
15int getDigitFromDouble(double, int);
16
17int main() {
18 clock_t t1 = clock();
19 // Time-wasting function
20 foo();
21 clock_t t2 = clock();
22
23 // Total sec., but including floating part, not only integer
24 double sec = (double)(t2 - t1) / CLOCKS_PER_SEC;
25 // 0.1 sec. part
26 int ssec = getDigitFromDouble(sec,1);
27 // Convert dobule to const time_t,
28 // Since localtime needs (const time_t*) parameter
29 const time_t time_t_sec = (time_t)sec;
30 // localtime() return (struct *tm)
31 struct tm* ts = localtime(&time_t_sec);
32
33 std::cout << "Total sec:" << sec << std::endl;
34 std::cout << "min:" << ts->tm_min << std::endl;
35 std::cout << "sec:" << ts->tm_sec << std::endl;
36 std::cout << "0.1 sec:" << ssec << std::endl;
37
38 return 0;
39}
40
41void foo() {
42 for(int i = 0; i != 1000000; ++i)
43 for(int j = 0; j != 100000; ++j);
44}
45
46// get specified floating point number from double
47int getDigitFromDouble(double d, int n) {
48 int t = 1;
49 for(int j = 0; j != n-1; ++j) {
50 t *= 10;
51 }
52
53 d = d * t;
54 int i = (int)d;
55
56 return (int)((double)(d-i)*10);
57}
本范例为了抓到0.1秒,所以才用了clock(),一般若只想抓到sec.,用time()即可。
See Also
(原創) 何抓出小数部份第n位数字? (C/C++)
Reference
C程序设计 500个应用范例技巧大全集 P.473, 平田 丰 着/ 黄正凯 译, 博硕文化